TI white paper "IQ: What is IQ and how to use it"
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This post was last edited by qwqwqw2088 on 2020-10-16 19:51
Introduction
A device's quiescent current, or IQ, is an important but often misused parameter for low-power, high-performance designs. In many battery-powered applications, the current drawn by the battery during light-load or no-load standby conditions determines the total system run time. In integrated switching converters, IQ is only a fraction of this battery current. This article defines IQ, explains how to measure it, explains what IQ is and when it should not be used, and explains some design considerations for using IQ while avoiding common measurement errors. This article applies to all Texas Instruments (TI) TPS61xxx, TPS62xxx, or TPS650xx devices.
What is IQ?
Unless otherwise specified in the data sheet, all IQ definitions are: the current drawn by the IC in its no-load, non-switching, but active state. "No load" means no current is being drawn by the IC. Typically, this is the current drawn through the SW pin on a buck converter, or through the VOUT pin on a boost converter. All IQ flows only through the IC's internal circuit to ground. "Non-switching" means no power switch in the IC is on (off). It includes the main switch or control switch, and if both are integrated into the IC, the synchronous rectifier. In other words, the IC is in a high impedance state with a power stage that is completely disconnected from the output (except for the integrated MOSFET body diode on some devices that cannot be turned off). "Active" means that the IC is turned on via its EN pin and is not in UVLO or other shutdown state. IQ measures the operating current, not the shutdown current, so the device must be turned on. Finally, IQ is only meaningful in power-saving mode, so if this mode is an option for a particular device, it must be active. If the device is running in pulse-width modulation (PWM) mode, the power stage input current and switching losses significantly reduce the amount of current, which is the IQ required to run the device.
IQ is fundamentally derived from two inputs: VIN and VOUT. The datasheet specifies whether IQ is derived from either or both pins. Figure 1 shows the IQ specification from the TI TPS61220/21/22 datasheet. The TI TPS61220/21/22 are all boost converters that pull their IQ from both VIN and VOUT. In general, a buck converter pulls IQ only from its input, while a boost or buck converter pulls IQ from both the input and output. IQ measures the current required to operate the basic functions of the device, which includes powering things like the internal precision reference, oscillator, thermal shutdown or UVLO circuits, the device state machine, or other logic gates. IQ does not include any input current to the power stage or gate driver because it is measured in a non-switching state where the current is zero. The reason IQ is measured in this state is that it depends only on the IC, while the power stage input current and gate drive current depend on the external components selected, which in most cases dictate how often the IC switches in its power saving mode. Therefore, IQ is an IC measurement, while the measurement that includes the other two currents is a system measurement. TI cannot control or guarantee this system measurement, but it can control and specify the IC measurement. In fact, TI guarantees the IQ specification, and for those devices that specify a maximum IQ in the datasheet, TI tests each device individually and tests every device produced. The testing process involves activating the device, setting it to the test conditions specified in the datasheet, and then artificially raising (applying voltage externally) the output voltage, the FB pin voltage, and all other pin voltages to a level high enough that the IC does not switch. With no load and the power-saving mode activated (if active), the input current to the IC becomes IQ.
Misunderstood IQ
IQ is not the no-load input current. As mentioned earlier, IQ is only the "overhead" current required to operate the basic functions of the IC. It does not include the input current of the power stage (the current that actually goes to the output), or the current required to operate the gate driver. Even in the no-load condition, the device is still switching to keep the output in regulation. Some losses are always present at the output, such as losses in the voltage divider used to set the output voltage; leakage current into the load or through the output capacitor; and pull-up resistors. Because these losses cause voltage decay at the output capacitor, the IC must switch frequently to compensate for the power loss. Thus, the no-load input current measurement violates the
requirement that the IC must be in a non-switching state and that there is no current for the IC to recharge VOUT. For example, Figure 2 shows the no-load operation of the TPS61220 boost converter with an input voltage of 1.2 V and an output voltage of 3.3 V. The IC switches approximately every 1.75 ms to regulate the output voltage. This interval depends on VIN, VOUT, and external components, and affects the amount of average current drawn. During Phase #1, the IC is switching—either the high-side MOSFET or the synchronous rectifier MOSFET is on. The input current is dominated by the current into the power stage, which averages about 7 mA (half the inductor peak current).
Figure 3 shows a larger view of phase #1. Once the output voltage drops below the threshold, the TPS61220 begins a switching pulse by turning on the control MOSFET. The SW pin goes low, causing the inductor current to ramp up. It then turns off the control MOSFET and then turns on the rectifier MOSFET, allowing current to flow to the output. As this energy enters the output capacitor, the output voltage rises. When the inductor current reaches zero, all the energy is transferred to the output; thus, the rectifier MOSFET turns off and the IC goes into sleep mode (phase #2). At this point, both MOSFETs are off (on), so the SW pin is in a high impedance state. The inductor and the parasitic capacitance of this pin ring until it reaches its DC value, which is equal to the input voltage. During phase #2, the IC is high impedance and the output voltage drops due to leakage at the output. Since the IC is not switching, the current consumed by the IC during this period is IQ. By calculating the average input current, phases #1 and #2 define a switching period. Due to the high input current during the switching period (Phase #1), the average input current during this time must be higher than the IQ of the IC. However, since the duration of Phase #1 is very short, the average input current is generally slightly larger than the input current due to IQ.
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