I recently wrote an STM32 program and used a union, which caused a question.
For example, 0x12345678 is stored in a U32 type variable. The big endian and little endian are stored like this.
Big-endian storage: Low address ... High address 0x 12 34 56 78 Little endian storage: Low address ... High address 0x 78 56 34 121234567
See the code
`#include "stm32f10x.h"
struct s
{
u32 a;
u8 b;
};
union B
{
u8 c[5];
struct s s_1;
};
union B BB;
int main(void)
{
BB.s_1.a=0x12345678;
BB.s_1.b=0x09;
while(1);
}`
Output:
It can be seen that the storage format is little-endian.
Be sure to pay attention when writing code in the future.
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