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Published on 2018-7-27 14:10
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There is no diode between pins 7 and 8. The upper left diode and the lower left diode in the first post are photodiodes. The 8th pin of D16 is connected to the positive terminal of the power supply, and both photodiodes are in reverse. When the photodiode is in reverse and without light, there is no current. When there is light (the light emitted by the right LED), although the photodiode is in reverse, there will be a small amount of current (the direction is from the positive terminal of the power supply). The current in this photodiode flows into the base of the transistor, becoming the base current of the transistor, making the transistor conduct. The transistor conduction reduces the potential of the input terminals D1A and D1B.
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Published on 2018-7-27 16:52
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Published on 2018-7-27 14:24
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qwqwqw2088
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3
Published on 2018-7-27 14:30
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Published on 2018-7-27 15:06
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7
Published on 2018-7-27 16:12
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Usually, it is Pin 1 and Pin 2. The FD2 signal usually does not exceed the power supply voltage (15V). Even if it exceeds, the two diodes in series in DAN217 are turned on, and the diode between pin 1 and pin 2 in D16 is reversed at this time, and will not be turned on, let alone short-circuited.
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Published on 2018-7-27 16:28
Usually, it is Pin 1 and Pin 2. The FD2 signal usually does not exceed the power supply voltage (15V). Even if it exceeds, the two diodes in series in DAN217 are turned on, and the diode between pin 1 and pin 2 in D16 is reversed at this time, and will not be turned on, let alone short-circuited.
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Published on 2018-7-27 16:24
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"Why doesn't it light up when it is at a high level, but lights up when it is at a low level?" The LED will not light up until the voltage of FD2 and FD3 is close to 15V. The reason why it does not light up at this time is that there is no current passing through the LED.
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Published on 2018-7-27 16:33
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Published on 2018-7-27 16:24
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Published on 2018-7-27 16:28
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Published on 2018-7-27 16:31
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15
Published on 2018-7-27 16:33
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Thank you, I understand now. I will study the circuit carefully.
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Published on 2018-7-27 16:44
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I understand. I looked up the working principle of photodiodes on the Internet, and found out that this is the case. . . . . . .
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Published on 2018-7-27 16:52
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Published on 2018-7-27 16:52
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