Why can't my INT function enter the interrupt?

yealien

Why can't my INT function enter the interrupt? [Copy link]

 

Why can't my RB0 port enter an interrupt? What's the problem?

#include<pic.h>
#include<pic16f877a.h>
#define uchar unsigned char
#define uint unsigned int
__CONFIG(0x3731);
void delay(uint x)
{
uint a,b;
for(a=x;a>0;a--)
for(b=110;b>0;b--);
}
void init() //initialization
{
OPTION_REG=0x00; //RBPU=0 enables the pull-up resistor of port B, INTEDG=0 triggers the falling edge interrupt
INTCON=0xD0; //GIE is 1 to allow general interrupts, INTE=1 enables RB0/INT external interrupts, INTF=0 clears the RB0 external interrupt flag
TRISB=0x01; //The lower 2 bits of port B are set to the keyboard input
TRISD=0; //The lower 4 bits of port D are set to the output of the LED
// PORTB=0x01;
PORTD=0; //Clear port D
}
void interrupt INT()
{
if(INTF==1) //Check if the interrupt flag is set to 1
{
INTF=0; //Clear interrupt flag
if(RB0==0) //Check if RB0 port is pressed again
{
PORTD=0x02; //Motor reverses
}
}
}
void main()
{
init();
while(1)
{
PORTD=0x00; //Motor reverses
}
}

okhxyyo

Any hint on the reason for the error?

dcexpert

The interrupt is not turned on.

yealien

Using ICD2 simulation, you can see that the interrupt position is 1, but you cannot enter the interrupt.

yealien

okhxyyo posted on 2020-6-28 05:58 Is there any hint for the error reason?

No error message. The interrupt can be set to 1, but the interrupt cannot be entered

yealien

dcexpert posted on 2020-6-28 09:04 The interrupt is not turned on

INTCON=0xD0; //GIE=1 enables general interrupt, INTE=1 enables RB0/INT external interrupt, INTF=0 clears RB0 external interrupt flag

With interrupt enabled

宋元浩

Help

dingzy_2002

yealien posted on 2020-6-30 20:25 Using ICD2 simulation, you can see the interrupt position 1, but you can't enter the interrupt.

I don't have the hardware for the PIC16F877A

Only through software simulation: Currently, it is possible to enter the interrupt. From the perspective of programming, the initialization section can be adjusted as follows:

①Set the pin level (PORTx→H, L);

②Set the pin direction (TRISx→input/output);

③Set the pull-up (if any);

④ Clear the relevant interrupt flags and set the interrupt enable bit;

⑤ Turn on the required general interrupt and external setting interrupt.

yealien

dingzy_2002 posted on 2020-7-6 16:03 I don't have the hardware of PIC16F877A, I only use software simulation: currently I can enter the interrupt. From the perspective of program writing, I can initialize this section...

void init() //initialization
{
OPTION_REG=0x00; //RBPU=0 enables the pull-up resistor of port B, INTEDG=0 triggers the falling edge interrupt
INTCON=0xD0; //GIE is 1 to allow general interrupts, INTE=1 enables RB0/INT external interrupts, INTF=0 clears the RB0 external interrupt flag
TRISB=0x01; //The lower 2 bits of port B are set to the input of the keyboard
TRISD=0; //The lower 4 bits of port D are set to the output of the LED
// PORTB=0x01;
PORTD=0; //Clear port D
}

That's right.

dingzy_2002

I usually write like this:

①:

// PORTB=0x01;
PORTD=0; // Port D cleared

②:

TRISB=0x01; //The lower 2 bits of port B are set as keyboard input
TRISD=0; //The lower 4 bits of port D are set as LED
output③

OPTION_REG=0x00; //RBPU=0 enables the pull-up resistor of port B, INTEDG=0 triggers the falling edge interrupt
INTCON=0xD0; //GIE is 1 to enable general interrupts, INTE=1 enables RB0/INT external interrupts, INTF=0 clears the RB0 external interrupt flag

yealien

dingzy_2002 posted on 2020-7-7 11:49 I usually write like this: ①: // PORTB=0x01; PORTD=0; &n ...

It seems to be the opposite of my order. I will try it tomorrow.

yealien

dingzy_2002 posted on 2020-7-6 16:03 I don't have the hardware of PIC16F877A, I only use software simulation: currently I can enter the interrupt. From the perspective of program writing, I can initialize this section...

I changed the order, but it still doesn't work.

dingzy_2002

yealien posted on 2020-7-10 18:54 I adjusted the order, but it still doesn't work.

I used software simulation, and I can enter the interrupt;

When hardware simulation is in progress, whether the interrupt is enabled or not depends mainly on the register configuration.

In my experience, observing register data changes more often will help you find problems more quickly.

yealien

dingzy_2002 posted on 2020-7-11 14:45 I used software simulation and can enter the interrupt; When hardware simulation, entering the interrupt mainly depends on the register configuration problem; In my opinion...

I have no problem using software simulation, but I can't enter the interrupt with hardware simulation

清越无情

Are GIE and PEIE open?