Why is this? After searching the Internet, I found many related discussion posts. Combined with my own understanding, I came to the following conclusion.
If you are interested, you can search for this keyword, 8-bit bitmap. It turns out that our second operand follows this rule.
The above explanation text comes from the ARM Processor Instruction Set, and two pictures are attached:
So, we can summarize it like this:
1. To determine whether a number conforms to the principle of 8-bit bitmap, first check whether the number of 1s in the binary representation of the number does not exceed 8. If not, then check whether these n 1s (n<=8) can be put into 8 binary bits at the same time. If they can be put in, then check whether these eight binary bits can be cyclically right-shifted by even bits to get the number we want to use. If so, this number conforms to the principle of 8-bit bitmap and is a legal immediate number. Otherwise, it does not conform.
2. The 32-bit number that cannot be represented can only be obtained through other means such as logical or arithmetic operations. For example, 0xFFFFFF00 can be obtained by bitwise inversion of 0x000000FF.
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Professor at Beihang University, dedicated to promoting microcontrollers and embedded systems for over 20 years.
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