The OP
Published on 2024-9-15 13:34
Only look at the author
This post is from Motor Drive Control(Motor Control)
Latest reply
Obviously, RC filtering cannot be used because the loss on the resistor is too large. Active filtering cannot be used because there is no amplifier with such a high power. As a result, only LC filtering is available. When using LC filtering, it is necessary to pay attention to the frequency response curve of the filter not having too large a peak, that is, the quality factor of LC must be controlled.
Details
Published on 2024-9-16 11:39
| ||
|
||
2
Published on 2024-9-15 14:08
Only look at the author
This post is from Motor Drive Control(Motor Control)
| ||
|
||
|
This post is from Motor Drive Control(Motor Control)
Comments
[It is derived from the fact that the rated current is twice the rated power] Current and power are not the same physical quantity. The unit of current is ampere, and the unit of power is watt. There is absolutely no multiple relationship between the two. You buy rice by the pound, and you buy cloth by the foot. There is no multiple relationship between the two either.
Details
Published on 2024-9-15 14:23
| ||
|
||
|
4
Published on 2024-9-15 14:23
Only look at the author
This post is from Motor Drive Control(Motor Control)
Comments | ||
|
||
|
This post is from Motor Drive Control(Motor Control)
Comments | ||
|
||
|
6
Published on 2024-9-15 15:04
Only look at the author
This post is from Motor Drive Control(Motor Control)
| ||
|
||
|
This post is from Motor Drive Control(Motor Control)
Comments
Let's not talk about "one kilowatt, two flows" nonsense, let's talk about filter design first. The 8th post said it very accurately: maintain the transmission efficiency of the fundamental wave (sine wave) and reduce the high-frequency harmonics in the inverter output. What you need is a low-pass filter. The carrier frequency must be outside the band of the low-pass filter, and the attenuation must be as large as possible. You need to convert the frequency
Details
Published on 2024-9-16 11:39
Let's not talk about "one kilowatt, two flows" nonsense, let's talk about filter design first. The 8th post said it very accurately: maintain the transmission efficiency of the fundamental wave (sine wave) and reduce the high-frequency harmonics in the inverter output. What you need is a low-pass filter. The carrier frequency must be outside the band of the low-pass filter, and the attenuation must be as large as possible. You need to convert the frequency
Details
Published on 2024-9-16 11:36
| ||
|
||
|
8
Published on 2024-9-15 19:21
Only look at the author
This post is from Motor Drive Control(Motor Control)
| ||
|
||
|
9
Published on 2024-9-16 11:36
Only look at the author
This post is from Motor Drive Control(Motor Control)
| ||
|
||
|
10
Published on 2024-9-16 11:39
Only look at the author
This post is from Motor Drive Control(Motor Control)
| ||
|
||
|
EEWorld Datasheet Technical Support
EEWorld
subscription
account
EEWorld
service
account
Automotive
development
circle
About Us Customer Service Contact Information Datasheet Sitemap LatestNews
Room 1530, Zhongguancun MOOC Times Building, Block B, 18 Zhongguancun Street, Haidian District, Beijing 100190, China Tel:(010)82350740 Postcode:100190