Limit parameter problem of transistor

小太阳yy

Limit parameter problem of transistor [Copy link]

It can be seen from the following specification that the transistor has three limit voltage parameters

VCBO, VCEO, VEBO

I understand that when VCEO withstands the voltage, it is the case of IB=0, that is, when B is open, the voltage of CE is the highest.

Why is E open when VCBO withstands voltage? Why is the voltage of CB the highest when E is open?

Also, why is C open circuit when EB withstands the voltage? Why is the voltage of EB the highest when C is open circuit?

maychang

[Why is the voltage of CB the highest when E is open? ]

If E is connected to C when measuring VCBO, the measured value is the emitter junction withstand voltage.

maychang

[Why is E open circuit when VCBO withstands voltage? ]

The letter O in VCBO means OPEN, which means open circuit. There are three poles in total. The withstand voltage between CB is measured, and the open circuit is naturally E.