PIC18F26K80 INT0 interrupt does not work, see where the problem is

djinter

PIC18F26K80 INT0 interrupt does not work, see where the problem is [Copy link]

void init()
{
OSCCONbits.IDLEN = 0;
OSCCONbits.IRCF2 = 1; //16MHz
OSCCONbits.IRCF1 = 1;
OSCCONbits.IRCF0 = 1;
OSCCONbits.SCS0 = 0; // Internal oscillator selected
OSCCONbits.SCS1 = 0;

LATB=0X00;
TRISBbits.TRISB0 = 1; //Configure RB0 input
TRISBbits.TRISB2 = 1;
TRISBbits.TRISB3 = 1;
TRISBbits.TRISB1 = 0; //Configure RB1 output, P1B
TRISBbits.TRISB4 = 0; //Configure RB4 output, P1A
TRISBbits.TRISB5 = 1; //Configure RB5 output

LATC=0X00;
TRISCbits.TRISC3 = 1; //Configure RC3 input
TRISCbits.TRISC4 = 0; //Configure RC4 output
TRISCbits.TRISC7 = 0; //Configure RC7 output

INTCON=0X00;
INTCONbits.GIE=1; //Turn on general interrupt
INTCONbits.PEIE=1; //Enable peripheral interrupt

INTCONbits.INT0IE=1; //Enable INT0 interrupt
INTCON2bits.INTEDG0=1; //INT0 rising edge interrupt
INTCONbits.INT0IF=0; //INT0 interrupt flag clear

}

void delay(unsigned int t_ms)
{
unsigned int j;
for(j=0;j<t_ms;j++);
}

void interrupt myIsr(void)
{

if(INTCONbits.INT0IF==1)
{
INTCONbits.INT0IF=0;
RC4=!RC4;
}
}

void main()
{
init();

while(1)
{
;
}
}

mzb2012

pic18 has two interrupt entries, one is the high vector and the other is the low vector. You did not specify the interrupt vector here, so you need to specify the interrupt entry address.

#pragma code high_vector = 0x08