I am a beginner who just learned 51. I would like to ask the experts to see if there is any problem with the program of the water lamp.

whxxxx

I am a beginner who just learned 51. I would like to ask the experts to see if there is any problem with the program of the water lamp. [Copy link]

#include "reg52.h" #include typedef unsigned int u16; typedef unsigned char u8;void delay(u16 z);sbit P10=P1^0;#define led P10;void delay(u16 i);{ while(i--); }void main(){ u8 i; led=~0x01; delay(50000); while(1) { for(i=0;i<7;i++) { P10=~(0x01<0;i--) {if(i%2 != 0) P10=~(0x01<0;i--){P10=~(0x01<

This is an error message

rrr.c(11): error C141: syntax error near '{' rrr.c(12): error C141: syntax error near '--', expected ')' rrr.c(18): error C141: syntax error near '='

When pasting the code, pay attention to the format.

P10=~(0x01<0;i--) This assignment operation is incorrect. There is no semicolon after the copy operation. P10=~(0x01<0);i--; Also, what is 0x01<0 for? Left shift is not this operator. I don't know what you wrote.


#include "reg52.h"
#include 
typedef unsigned int u16;
typedef unsigned char u8;
void delay(u16 z);
sbit P10=P1^0;
#define led P10;
void delay(u16 i);
{
    while(i--);
}
void main(){
    u8 i;
    led=~0x01;
    delay(50000);
    while(1) {
        for(i=0;i<7;i++) {
            P10=~(0x01<0;i--) {
                if (i%2 != 0) 
                    P10=~(0x01<0;i--) {
                        P10=~(0x01<

It is best not to use i-- in the for loop, as it will cause confusion

Yours is lit at low level, can you tell me what this means? P10=~(0x01<0;i--) The left shift symbol should be: "《"

I am a beginner who just learned 51. I would like to ask the experts to see if there is any problem with the program of the water lamp.

whxxxx

#include "reg52.h" #include typedef unsigned int u16; typedef unsigned char u8;void delay(u16 z);sbit P10=P1^0;#define led P10;void delay(u16 i);{ while(i--); }void main(){ u8 i; led=~0x01; delay(50000); while(1) { for(i=0;i<7;i++) { P10=~(0x01<0;i--) {if(i%2 != 0) P10=~(0x01<0;i--){P10=~(0x01<

This is an error message

rrr.c(11): error C141: syntax error near '{' rrr.c(12): error C141: syntax error near '--', expected ')' rrr.c(18): error C141: syntax error near '='

When pasting the code, pay attention to the format.

P10=~(0x01<0;i--) This assignment operation is incorrect. There is no semicolon after the copy operation. P10=~(0x01<0);i--; Also, what is 0x01<0 for? Left shift is not this operator. I don't know what you wrote.


#include "reg52.h"
#include 
typedef unsigned int u16;
typedef unsigned char u8;
void delay(u16 z);
sbit P10=P1^0;
#define led P10;
void delay(u16 i);
{
    while(i--);
}
void main(){
    u8 i;
    led=~0x01;
    delay(50000);
    while(1) {
        for(i=0;i<7;i++) {
            P10=~(0x01<0;i--) {
                if (i%2 != 0) 
                    P10=~(0x01<0;i--) {
                        P10=~(0x01<

It is best not to use i-- in the for loop, as it will cause confusion

Yours is lit at low level, can you tell me what this means? P10=~(0x01<0;i--) The left shift symbol should be: "《"

I am a beginner who just learned 51. I would like to ask the experts to see if there is any problem with the program of the water lamp.

whxxxx

#include "reg52.h" #include typedef unsigned int u16; typedef unsigned char u8;void delay(u16 z);sbit P10=P1^0;#define led P10;void delay(u16 i);{ while(i--); }void main(){ u8 i; led=~0x01; delay(50000); while(1) { for(i=0;i<7;i++) { P10=~(0x01<0;i--) {if(i%2 != 0) P10=~(0x01<0;i--){P10=~(0x01<

This is an error message

rrr.c(11): error C141: syntax error near '{' rrr.c(12): error C141: syntax error near '--', expected ')' rrr.c(18): error C141: syntax error near '='

When pasting the code, pay attention to the format.

P10=~(0x01<0;i--) This assignment operation is incorrect. There is no semicolon after the copy operation. P10=~(0x01<0);i--; Also, what is 0x01<0 for? Left shift is not this operator. I don't know what you wrote.


#include "reg52.h"
#include 
typedef unsigned int u16;
typedef unsigned char u8;
void delay(u16 z);
sbit P10=P1^0;
#define led P10;
void delay(u16 i);
{
    while(i--);
}
void main(){
    u8 i;
    led=~0x01;
    delay(50000);
    while(1) {
        for(i=0;i<7;i++) {
            P10=~(0x01<0;i--) {
                if (i%2 != 0) 
                    P10=~(0x01<0;i--) {
                        P10=~(0x01<

It is best not to use i-- in the for loop, as it will cause confusion

Yours is lit at low level, can you tell me what this means? P10=~(0x01<0;i--) The left shift symbol should be: "《"

I am a beginner who just learned 51. I would like to ask the experts to see if there is any problem with the program of the water lamp.

whxxxx

This is an error message

whxxxx

This is an error message

whxxxx

rrr.c(11): error C141: syntax error near '{'
rrr.c(12): error C141: syntax error near '--', expected ')'
rrr.c(18): error C141: syntax error near '='

chenzhufly

When pasting the code, pay attention to the format.

曹伟1993

P10=~(0x01<0;i--) This assignment operation is incorrect. There is no semicolon after the copy operation. P10=~(0x01<0);i--; Also, what is 0x01<0 for? Left shift is not this operator. I don't know what you wrote.

freebsder


#include "reg52.h"
#include 
typedef unsigned int u16;
typedef unsigned char u8;
void delay(u16 z);
sbit P10=P1^0;
#define led P10;
void delay(u16 i);
{
    while(i--);
}
void main(){
    u8 i;
    led=~0x01;
    delay(50000);
    while(1) {
        for(i=0;i<7;i++) {
            P10=~(0x01<0;i--) {
                if (i%2 != 0) 
                    P10=~(0x01<0;i--) {
                        P10=~(0x01<

huo_hu

It is best not to use i-- in the for loop, as it will cause confusion

generalcircuits

Yours is lit at low level, can you tell me what this means? P10=~(0x01<0;i--) The left shift symbol should be: "《"

I am a beginner who just learned 51. I would like to ask the experts to see if there is any problem with the program of the water lamp. [Copy link]

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