Use external interruption and time interruption to count 0-999 and display it on the digital tube

Requirements: The digital tube starts displaying from 0. Press a key once (and the internal interrupt, it will naturally enter an interrupt once every second). When an interrupt is entered, the number on the digital tube increases by 1 until it reaches 999, and then starts from 0 again.

Connection: P10 to L7, potentiometer to DC motor, pulse output to P32, CS1 to digital tube CS

#include

typedef unsigned char uchar;

xdata uchar LED_CS _at_ 0x9000;

xdata uchar LED_OUTSEG _at_ 0x9004;

xdata uchar LED_OUTBIT _at_ 0x9002;

sbit P10=P1^0;

fly n=0;

unsigned int Count=0;

code unsigned char LEDMAP[]={

//Eight-segment tube display code

0x3f, 0x06, 0x5b, 0x4f, 0x66, 0x6d, 0x7d, 0x07,

0x7f, 0x6f, 0x77, 0x7c, 0x39, 0x5e, 0x79, 0x71

};

code unsigned char LEDWED[]= {0x20,0x10,0x08,0x04,0x02,0x01};

//Display buffer

uchar led_buf[]={0,0,0};

void delay(unsigned char ms)

{

unsigned char i;

while(ms--)

{

for(i = 0; i < 50; i++);

}

}

void ADcal()

{

led_buf[0]=Count/100;//hundreds place

led_buf[1]=Count/10%10;//ten digit

led_buf[2]=Count%10;

}

//Open time interrupt

void initTime(){

IE=0x83;

TR0=1;

}

//Open external interrupt

void initOut(){

IE=0x83;

IT0=1;

}

void timer0() interrupt 1

{

TH0=(65535-50000)/256;

TL0=(65535-50000)%256;

n++;

if(n==2)

{

P10=1;

delay(20);

P10=0;

delay(20);

Count++;

if(Count>=999)

{

Count=0;

}

}

}

void out0() interrupt 0

{

Count++;

if(Count>=999)

{

Count=0;

}

}

void main()

{

unsigned int i=0;

initOut(); //Open external interrupt'

initTime();

TH0=(65535-50000)/256;

TL0=(65535-50000)%256;

delay(10);

while(1)

{

ADcal();

LED_CS=0;

if(i==0)

{

LED_OUTSEG=LEDMAP[led_buf[i]];

}

if(i==1)

{

LED_OUTSEG=LEDMAP[led_buf[i]];

}

if(i==2)

{

LED_OUTSEG=LEDMAP[led_buf[i]];

}

LED_OUTBIT=LEDWED[i];

i++;

i=i%3;

delay(10);

}

}