(*(void(*)())0) () Explanation - Alternative reset of MCU

(*(void(*)())0) ();

Prerequisites

float (*h)();

Indicates that h is a pointer to a function that returns a float value.

(float(*)())

A type conversion symbol that represents a "pointer to a function that returns a float value"

Assuming fp is a function pointer, how to call the function pointed to by fp is as follows:

 (*fp)();

According to people's habitual thinking, we can write

(*0)();

The above formula does not work because the operator * must take a pointer as an operand, and this pointer must be a function pointer. So we have to force 0 to be converted into a function pointer (a pointer to a function with a return value of type void)

Assume fp is a float pointer, declared as follows

float * fp;

Force 0 to be converted into a float pointer (just remove the variable fp)

(float *)0;

similar:

Assume that fp is a pointer to a function of type void), the declaration is as follows:

void (*fp)();     

Force 0 to be converted into the function pointer (just remove the variable fp)

(void(*)())0

Finally, replace fp with (void(*)())0 to get the usage of calling

(*(void(*)())0) ();

Typedef can be used to simplify function pointers

For example:

typedef char * string;

string test="hello";

similar

typedef void(*func)(); // In this way, func represents the type of a function pointer

(*(func)0)();

example

method one:

typedef void (*pfunction)(void);

 void FMI_Jump(void)
{   
  pfunction jump;
  jump=(pfunction)(0x80000);
  jump();
  
}

 Method Two:

((void(code *)(void))0xF400)();