MIT Introduction to Digital Systems 2 Lecture #2 MIT Department of Electrical Engineering and Computer Science 6.111 Introduction to Digital Systems Lab Basic Concepts (related to digital logic…) The values (x and y) here represent something like voltage (is it +5 volts (1) or zero (0))? Or a light on or off? AND: OR: (that is, any thing that can be represented by a binary value) NOT: Identity: Basic: MIT Department of Electrical Engineering and Computer Science 6.111 Introduction to Digital Systems Experiment Commutative Law of Boolean Algebra: Distributive Law: Absorbing Law: Others: De Morgan\'s Theorem: Dual: MIT Department of Electrical Engineering and Computer Science 6.111 Introduction to Digital Systems Experiment Proof of De Morgan\'s Theorem: MIT Department of Electrical Engineering and Computer Science 6.111 Introduction to Digital Systems Experiment Massachusetts Stop Light Example F = 1 means the stop light is working properly F = 0 means the stop light is broken Truth table: MIT Department of Electrical Engineering and Computer Science 6.111 Introduction to Digital Systems Experiment Old Stop Light Example: Using Boolean Simplification F = R * /Y * /G + /R * Y * /G + /R * /Y * G + R * Y */G Step 1: Since Y + /Y = 1 R*/Y*/G + /R*Y*/G = R*(Y + /Y) * /G = R * /GF=R * /G + /R * Y * /G + /R * /Y * G Step 2: Use the absorption law: R + /R * Y = R + YR*/G + /R * Y * /G =(R +/R * Y) * /G = (R + Y) * /GF=(R + Y) * /G + /R * /Y * G =R * /G +Y * /G + /R * /Y *G Use De Morgan\'s Theorem: /F=((R * /Y) + G) *(/G +(R * Y)) = /R*/Y*/G + G * (R + Y) Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science 6.111 Introduction to Digital Systems Experiment Truth table: …
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