Production of electric water bottle energy saver
Source: InternetPublisher:张三叔 Keywords: Insulation circuit Updated: 2024/09/27
Production of electric water bottle energy saver
According to the working principles of different types of electric thermos published in your newspaper and related magazines, the author believes that the main power-consuming parts are the main heater and the insulation heater. The heating power of the former is about 680W~700W, and the latter is 35W~40W. The constant temperature of hot water is about 87℃~99℃. According to the working principle analysis, after the raw water in most electric thermos is heated to the insulation state by the main heater, in order to compensate for the heat loss of the hot water, power is continued to be supplied to the insulation heater, so that the water temperature is kept within the required temperature range.
For this purpose, the author uses a 3L electric water bottle with a 700W main heater and a 40W insulation heater to calculate the power consumed after 12 hours of insulation. The power consumption of the former after 25 minutes of boiling water until the insulation indicator light is on is 0.7kW x0.416h=0.29kWh, and the latter is 0.04kWxl2h=0.48kWh, accounting for about 62.3% of the total power consumption. If the electric water bottle can use a fully adjustable energy saver as shown in the attached figure, the annual single electricity bill can be reduced by about 70%. Practice shows that if the energy saver is calculated based on 25 seconds of heating and 60 seconds of power outage within 12 hours, its power consumption is only 0.14kWh. So from the current heating method of electric water bottles. The author believes that about 70% of the electric energy of electric water bottles is wasted in vain during the insulation process. The energy saver is set up by utilizing the thermal inertia of hot water. The actual measured water temperature is still maintained within the required range of 87% to 95°C, so it can indeed achieve maximum energy saving effect.
How it works
After the mains voltage is reduced by C1 and R1 and rectified, stabilized and filtered by VD1~VD5 and C2, the 12V DC voltage is supplied to the 555 integrated circuit. At the moment of power on, because the voltage across C3 cannot change suddenly, the 555 pins ⑥ and ② are at low potential, the R~S trigger composed of the 555 circuit is in reset state, the output end of pin ③ is at high potential, the red light of VD9 is on, the relay K is energized and attracted, the 4 pairs of normally open contacts J-<3:0> in the figure are closed, and the electric water bottle is heated by electricity. At the same time, the discharge tube in the IC is cut off, and the power supply charges C3 for the first time through R2, VD6, R3 and the low resistance value of the a end of RP. It is heated in a heat preservation state after about 45 seconds. At this time, the red light on the electric water bottle is still on. When the capacitor C3 is charged, the potential of the IC pin ⑥ is increased from 0V to 2/3VCC high potential at the moment, the trigger in the circuit is reset and flipped, and the pin ③ is at low potential.
The green light of VDl0 lights up, and the relay K loses power, so that the electric water bottle starts to be in the energy-saving state. At this time, the discharge tube in the IC is turned on, and its discharge terminal ⑦ pin is short-circuited to the ground ① pin. The charge stored in C3 is discharged through the right half RP with higher resistance, VD7 and the discharge tube for 60 seconds. At this time, the electric water bottle is in the power-off heating state. When the potential of the trigger terminal ② pin drops to 1/3Vcc, the trigger resets the ③ pin to output a high potential red light, and the relay K is energized again to attract the normally open contact to close. At this time, the thermal insulation heater only heats for 25 seconds, so the ③ pin presents a cycle of short-term heating for 25 seconds when the potential is high and long-term power outage for 60 seconds when the potential is low, thereby achieving a very significant energy-saving effect.
When making, the resistance value of R3 in the figure should be selected according to the temperature difference in the region to select the appropriate starting charging time. The charging time can be estimated as 0.693 (R2 + R3) C3, and then adjusted in actual use.
Secondly, connect the four pairs of normally open contacts J-<3:O> of relay K in parallel to increase its contact capacity and safety.
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