Use a two-stage toggle switch to realize two sets of LED lighting states (power supply is DC5V)

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Use a two-stage toggle switch to realize two sets of LED lighting states (power supply is DC5V) [Copy link]

Use a two-stage toggle switch to realize two groups of LED lighting states (power supply is DC5V).

There is an actual test fixture that needs to realize 5 LEDs lighting up at the same time and 1 LED lighting up, and the other LEDs are off. MCU or other logic devices cannot be used, so two solutions came to mind. The first solution is undoubtedly the best! The second and third solutions are the same. There is nothing to say about the first solution. Pure mechanical switches can be implemented. The second solution has a problem. When using IN4148 (the horizontal diode), the switch is toggled to the far right. At this time, only the right LED can light up, that is, there is voltage, but it is not. There is also a voltage of 0.5V on the left side of IN4148, but it cannot carry a load, and the LED cannot light up. If 4148 is replaced with SS34, the virtual electricity on the left can reach 5V, and it cannot carry a load.

Question: Is the reverse leakage current of IN4148 smaller than that of SS34? That is, the leakage current of Schottky diode SS34 is too large, resulting in virtual electricity on the left? Should the reverse recovery time of Schottky diode also be considered? In this case, when choosing a diode for isolation, what specifications of the diode should be considered?

tagetage

Just use 1N4007, no need to consider Schottky or recovery time.

led2015

In terms of reverse leakage current, the reverse leakage current of IN4148 is relatively small and is suitable for low voltage and low power applications, while the reverse leakage current of SS34 is relatively large and is suitable for high frequency applications.