The OP
Published on 2022-6-25 09:36
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The parameter you are looking at refers to the maximum collector dissipation power, which is the heat dissipation capacity from the junction temperature to the environment determined by the package. It is not what you understand as calculating the current. In addition, in addition to the voltage and current limit parameters, it is best to refer to the SOA curve when looking at the operating current. Your saturation voltage drop should still be referenced. Which curve is more suitable for VCE voltage drop and IC current?
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Published on 2022-6-27 09:17
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It says on the picture: MAXMUM RATINGS, which obviously does not mean "no matter how much the current is, it is always 1.5W during operation". Just as the maximum current in the picture is 8A, it obviously does not mean that the current is always 8A no matter what state the transistor is in. 1.5W, 8A, 100V, etc. are all maximum allowable values, that is, they must not be exceeded. If exceeded, the transistor will
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Published on 2022-6-25 14:10
It says on the picture: MAXMUM RATINGS, which obviously does not mean "no matter how much the current is, it is always 1.5W during operation". Just as the maximum current in the picture is 8A, it obviously does not mean that the current is always 8A no matter what state the transistor is in. 1.5W, 8A, 100V, etc. are all maximum allowable values, that is, they must not be exceeded. If exceeded, the transistor will
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Published on 2022-6-25 11:32
It says on the picture: MAXMUM RATINGS, which obviously does not mean "no matter how much the current is, it is always 1.5W during operation". Just as the maximum current in the picture is 8A, it obviously does not mean that the current is always 8A no matter what state the transistor is in. 1.5W, 8A, 100V, etc. are all maximum allowable values, that is, they must not be exceeded. If exceeded, the transistor will
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Published on 2022-6-25 10:36
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3
Published on 2022-6-25 10:36
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4
Published on 2022-6-25 11:32
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The current between the base and the emitter multiplied by the emitter junction voltage drop is the emitter junction power consumption. The emitter junction voltage drop is usually around 0.7V, and the current is several milliamperes, so the emitter junction power consumption is several milliwatts.
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Published on 2022-6-25 14:07
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Published on 2022-6-25 14:07
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7
Published on 2022-6-25 14:10
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My question is that I don't know how to understand the power of 1.5W. Transistors and diodes have a fixed voltage drop. For example, if the transistor is 0.7V, 1.5W/0.7V=2.14A, then it is impossible for the transistor to have a current of 8A flowing through it.
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Published on 2022-6-25 14:17
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"My problem is that I don't know how to understand the power of 1.5W." I have already said on the third floor: the picture says: MAXMUM RATINGS, which means the maximum level. Vcbo is 100V, which means that if Vcbo exceeds 100V, the tube may be damaged. Vebo is 5V, which means that if Vebo exceeds 5V, it may be damaged. Pc is 1.5W, which means that if Pc exceeds 1
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Published on 2022-6-25 14:35
"My problem is that I don't know how to understand the power of 1.5W." I have already said on the third floor: the picture says: MAXMUM RATINGS, which means the maximum level. Vcbo is 100V, which means that if Vcbo exceeds 100V, the tube may be damaged. Vebo is 5V, which means that if Vebo exceeds 5V, it may be damaged. Pc is 1.5W, which means that if Pc exceeds 1
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Published on 2022-6-25 14:34
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Published on 2022-6-25 14:34
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10
Published on 2022-6-25 14:35
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"Isn't the BE of a transistor a "diode"? I always thought there must be a 0.7V voltage drop between BE and the diode." The first sentence is generally correct. There is indeed a PN junction between BE and the diode. The second sentence is obviously wrong. If there is no current between BE and the diode (for example, the transistor has not been opened), the 0.7V voltage drop will definitely
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Published on 2022-6-25 15:13
"Isn't the BE of a transistor a "diode"? I always thought there must be a 0.7V voltage drop between BE and the diode." The first sentence is generally correct. There is indeed a PN junction between BE and the diode. The second sentence is obviously wrong. If there is no current between BE and the diode (for example, the transistor has not been opened), the 0.7V voltage drop will definitely
Details
Published on 2022-6-25 15:11
"Isn't the BE of a transistor a "diode"? I always thought there must be a 0.7V voltage drop between BE and the diode." The first sentence is generally correct. There is indeed a PN junction between BE and the diode. The second sentence is obviously wrong. If there is no current between BE and the diode (for example, the transistor has not been opened), the 0.7V voltage drop will definitely
Details
Published on 2022-6-25 15:09
"Isn't the BE of a transistor a "diode"? I always thought there must be a 0.7V voltage drop between BE and the diode." The first sentence is generally correct. There is indeed a PN junction between BE and the diode. The second sentence is obviously wrong. If there is no current between BE and the diode (for example, the transistor has not been opened), the 0.7V voltage drop will definitely
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Published on 2022-6-25 15:04
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12
Published on 2022-6-25 15:04
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The structure between the transistor CE is a meat-stuffed bun, but the thickness of the meat layer is controlled by the current of BE. If you want to leak oil through the meat layer, there must be a minimum pressure ground. Therefore, there should be a minimum voltage to overcome the minimum voltage drop, just like a diode.
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Published on 2022-6-25 15:19
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Published on 2022-6-25 15:09
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Published on 2022-6-25 15:11
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Published on 2022-6-25 15:13
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I will do an experiment to see if the voltage drop of CE is fixed when the transistor is saturated.
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Published on 2022-6-25 15:50
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Published on 2022-6-25 15:50
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Published on 2022-6-25 15:52
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Published on 2022-6-27 09:17
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