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These are two different power supplies. Can I collect the voltage drop of R0? Get the AD value of the voltage, divide it by the resistance value, and then... [Copy link]

These are two different power supplies. Can I collect the voltage drop of R0? I get the AD value of the voltage and divide it by the resistance value to get the static power consumption of the calibrated board. Is this method feasible?

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“The goal is to use the fixture to semi-automatically measure the static power consumption of the product.” The sampling resistor used for measurement must be connected in series with the power supply to the board.   Details Published on 2020-12-8 12:20
 
 

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"Is it feasible to get the AD value of the voltage and divide it by the resistance value to get the static power consumption of the calibrated board?"

Not feasible.

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It is impossible for such an independent power supply to have current flowing through R0? There is no loop, right?  Details Published on 2020-12-8 11:30
It is impossible for such an independent power supply to have current flowing through R0? There is no loop, right?  Details Published on 2020-12-8 11:29
 
 
 

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maychang posted on 2020-12-7 20:52 "Is it feasible to get the AD value of the voltage and divide it by the resistance value to get the static power consumption of the calibrated board?" Not feasible...

It is impossible for such an independent power supply to have current flowing through R0? There is no loop, right?

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“With such an independent power supply, it is impossible for current to flow through R0? There is no loop, right?” Yes.  Details Published on 2020-12-8 12:19
 
 
 

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maychang posted on 2020-12-7 20:52 "Is it feasible to get the AD value of the voltage and divide it by the resistance value to get the static power consumption of the calibrated board?" Not feasible...

Do you have any good method? The purpose is to use the fixture to semi-automatically measure the static power consumption of the product

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"The purpose is to use a fixture to semi-automatically measure the static power consumption of the product." The sampling resistor used for measurement must be connected in series with the power supply to the circuit board.  Details Published on 2020-12-8 12:20
 
 
 

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QWE4562009 posted on 2020-12-8 11:29 It is impossible for such an independent power supply to have current flowing through R0? There is no loop, right?

"With such an independent power supply, it is impossible for current to flow through R0? There is no loop, right?"

yes.

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QWE4562009 posted on 2020-12-8 11:30 Do you have any good method? The purpose is to use a fixture to semi-automatically measure the static power consumption of the product

“The goal is to use the fixture to semi-automatically measure the static power consumption of the product.”

The sampling resistor used for measurement must be connected in series with the power supply to the board.

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Yes, the series connection has been achieved. The two GNDs are closed by a relay. Why is there still a resistor? About 3K   Details Published on 2020-12-9 09:25
 
 
 

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maychang published on 2020-12-8 12:20 "The purpose is to use the fixture to semi-automatically measure the static power consumption of the product." The sampling resistor used for measurement must be connected to the power supply to the circuit board...

Yes, the series connection has been achieved. The two GNDs are closed by a relay. Why is there still a resistor? About 3K

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