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How does the schematic diagram work? [Copy link]

 
 

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When P1-pin2 has a positive pulse, the electricity is first rectified and stored in C1, and then waits for the arrival of the positive pulse of P1-pin2. When P1-Pin2 inputs a positive pulse, it is rectified and stored in C3, and then DCDC U3 is started, and then DVCC outputs the working voltage. Subsequently, DVCC triggers Q2 to turn on, so that the electricity previously stored in C1 flows to DCDC (U3) through Q2 and is used.  Details Published on 2021-1-28 16:52
 
 

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The circuit is wrong, what is the purpose of the Power part?

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The original poster did not explain what the P1 input is, so we can only guess. If it is two power sources from different sources, then the expression is incorrect and the circuit cannot be established without it. If it is AC input or non-polarity power input, then the diagram does not show the necessity of Q1 and Q2. Therefore, first clarify the actual circuit or design purpose.

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The DC-DC part is a typical Buck circuit of a 5-pin chip.

What is the control of the P1 preamplifier in the Power section?

 
 
 

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chunyang posted on 2020-9-3 21:40 The original poster did not explain what the P1 input is, so we can only guess. If it is two different sources of power, then the expression is wrong, and it cannot be established without a circuit. If it is an alternating...

The input is a pulse signal, which can be understood as the following picture

Comments

This waveform still cannot explain the problem of the two VIN numbers in the left figure on the first floor. Note that the two VINs are connected together in the circuit.  Details Published on 2020-9-4 15:40
This waveform still cannot explain the problem of the two VIN numbers in the left figure on the first floor. Note that the two VINs are connected together in the circuit.  Details Published on 2020-9-4 15:29
This waveform still cannot explain the problem of the two VIN numbers in the left figure on the first floor. Note that the two VINs are connected together in the circuit.  Details Published on 2020-9-4 15:27
 
 
 

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qwqwqw2088 posted on 2020-9-3 22:41 The DC-DC part is a typical Buck circuit of a 5-pin chip. What is the control of the P1 pre-stage of the Powe part?

The input is a pulse signal, which can be understood as the following picture

 
 
 

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I am a little white posted on 2020-9-4 08:17 The input is a pulse signal, which can be understood as the following picture

This waveform still cannot explain the problem of the two VIN numbers in the left figure on the first floor. Note that the two VINs are connected together in the circuit.

 
 
 

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I am a little white posted on 2020-9-4 08:17 The input is a pulse signal, which can be understood as the following picture

In addition, the socket P1 has two pins, but the author only drew the waveform of one of the pins, and did not specify which pin this waveform is for.

 
 
 

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I am a little white posted on 2020-9-4 08:17 The input is a pulse signal, which can be understood as the following picture

Still not clear...

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It's first high up and low down, then high down and low up.

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That is definitely wrong. There is not even a reference point. If the signal source shares a common ground with your circuit, you must draw it out, and it should be connected using a 3-pin connector.  Details Published on 2020-9-4 16:08
That is definitely wrong. There is not even a reference point. If the signal source shares a common ground with your circuit, you must draw it out, and it should be connected using a 3-pin connector.  Details Published on 2020-9-4 16:03
 
 
 

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maychang posted on 2020-9-4 15:27 Such a waveform still cannot explain the problem of the two VIN labels in the left picture on the first floor. Note that the two VINs are connected together in the circuit.

First it's high up and low down, then it's high down and low up, but not at the same time.

 
 
 

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I am a little white and posted on 2020-9-4 15:48 It is first high up and low down, then high down and low up

That is definitely wrong. There is not even a reference point. If the signal source shares a common ground with your circuit, you must draw it out, and it should be connected using a 3-pin connector.

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This post was last edited by maychang on 2020-9-4 16:17
I am a little white published on 2020-9-4 15:48 It is first high up and low down, then high down and low up.

Then, the signal between the two pins at the socket P1 is floating relative to the ground.

In this way, the four diodes D1 to D4 can charge the capacitors C1 and C3, and the voltage across the two capacitors C1 and C3 is close to the peak value of the input signal.

But no matter what the signal at P1 looks like, it cannot explain the problem of the two VINs on the left side of the first floor picture. As chunyang pointed out on the second floor: "What is the purpose of the Power part?"

 
 
 

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chunyang posted on 2020-9-4 16:03 That is definitely wrong. There is not even a reference point. If the signal source shares the same ground with your circuit, you must draw it out, and it should be connected with a 3-pin connector.

I think Q1 is about flow expansion and Q2 is about protection.

Comments

Q1 cannot expand current. The current output by Q1 collector cannot exceed the current provided by diode D2. Q1 collector should not be connected to the upper end of C3.  Details Published on 2020-9-4 16:41
Q1 cannot expand current. The current output by Q1 collector cannot exceed the current provided by diode D2. Q1 collector should not be connected to the upper end of C3.  Details Published on 2020-9-4 16:17
 
 
 

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I am a little white and posted on 2020-9-4 16:10 I think Q1 is to expand the flow, and Q2 is to protect.

Q1 cannot expand current. The current output from the collector of Q1 cannot exceed the current provided by diode D2.

The collector of Q1 should not be connected to the upper end of C3.

 
 
 

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I am a little white and posted on 2020-9-4 16:10 I think Q1 is to expand the flow, and Q2 is to protect.

Whose flow is being expanded? How is it being expanded? Who is being protected? How is it being protected?

Opinions need to be supported by evidence.

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This is a practically verified circuit, it is feasible and can obtain a regulated output. Please take a look at the principle and analyze it.
 
 
 

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I actually found the picture I drew. This is a polarity pulse and polarity detection circuit:
 
 
 

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When P1-pin2 has a positive pulse, the electricity is first rectified and stored in C1, and then waits for the arrival of the positive pulse of P1-pin2. When P1-Pin2 inputs a positive pulse, it is rectified and stored in C3, and then DCDC U3 is started, and then DVCC outputs the working voltage. Subsequently, DVCC triggers Q2 to turn on, so that the electricity previously stored in C1 flows to DCDC (U3) through Q2 and is used.
 
 
 

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