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QWE4562009
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Published on 2019-12-19 09:03
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A pure number is dimensionless, which does not mean it has no units. For example, an angle is defined as the ratio of the length of an arc to its radius. The ratio of two lengths is, of course, a pure number. But an angle has a unit, the unit being radians. An angle has a dimension of 1, or it has no dimensions.
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Published on 2019-12-23 14:48
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Published on 2019-12-19 10:11
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It's all about the frequency of the input signal.
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Published on 2019-12-19 10:35
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Published on 2019-12-19 10:13
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Published on 2019-12-19 10:15
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Published on 2019-12-19 10:16
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How are 0.707 and -3DB converted? -3DB=LgX?
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Published on 2019-12-19 12:10
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QWE4562009
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Published on 2019-12-19 10:52
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The cutoff frequency should be related to the input frequency. When it reaches this frequency, the signal will attenuate immediately.
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Published on 2019-12-19 12:11
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QWE4562009
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The definition of "Bel" is the common logarithm of the ratio of two powers, i.e. lg(P2/P1). "Decibel" is abbreviated as "decibel", recorded as dB, and is defined as one tenth of a Bel, i.e. 10lg(P2/P1).
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Published on 2019-12-23 15:41
The definition of "Bel" is the common logarithm of the ratio of two powers, i.e. lg(P2/P1). "Decibel" is abbreviated as "decibel", recorded as dB, and is defined as one tenth of a Bel, i.e. 10lg(P2/P1).
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Published on 2019-12-19 12:44
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QWE4562009
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This post is from Integrated technical exchanges
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As mentioned before: if there is no input signal, the cutoff frequency remains the same. No matter how the input signal frequency changes (same or different from the resonant frequency, same or different from the cutoff frequency), the cutoff frequency will not change. Therefore, the cutoff frequency has nothing to do with the input signal frequency. The cutoff frequency is determined by the LC filter circuit itself.
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Published on 2019-12-19 12:49
As mentioned before: if there is no input signal, the cutoff frequency remains the same. No matter how the input signal frequency changes (same or different from the resonant frequency, same or different from the cutoff frequency), the cutoff frequency will not change. Therefore, the cutoff frequency has nothing to do with the input signal frequency. The cutoff frequency is determined by the LC filter circuit itself.
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Published on 2019-12-19 12:47
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Published on 2019-12-19 12:41
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Published on 2019-12-19 12:44
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What are P1 and P2 here?
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Published on 2019-12-23 10:57
What are P1 and P2 here?
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Published on 2019-12-23 10:46
What are P1 and P2 here?
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Published on 2019-12-19 14:08
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Published on 2019-12-19 12:47
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Published on 2019-12-19 12:49
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QWE4562009
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Published on 2019-12-19 14:14
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Published on 2019-12-19 14:42
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Output P2/Input P1, right? Why do some of them show 20lg instead of 10lg?
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Published on 2019-12-23 10:42
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QWE4562009
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If the comparison is not between two power values, but between two voltage values or two current values (current values are rare), then it becomes 20lg, because power is proportional to the square of voltage (power is also proportional to the square of current).
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Published on 2019-12-23 11:29
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QWE4562009
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This post is from Integrated technical exchanges
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The power unit has disappeared in (P2/P1). I have posted a post discussing elementary functions. The independent variable of a logarithmic function must be a dimensionless pure number, and its result (function value) must also be a dimensionless pure number. Therefore, Bel (or decibel) is dimensionless.
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Published on 2019-12-23 11:27
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QWE4562009
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I don't know whether the calculator that comes with your computer can calculate the antilogarithm. However, since your computer can calculate the antilogarithm of a positive number, use a positive number (absolute value) to calculate. The reciprocal of the result of the calculation with a positive number is the result of calculating the antilogarithm with a negative number. For example, the antilogarithm of 0.30103 is 2, -0.30103
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Published on 2019-12-23 11:34
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Published on 2019-12-23 11:27
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What does a dimensionless pure number mean? No units?
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Published on 2019-12-23 14:42
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