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Is there any relationship between the cutoff frequency and the resonant frequency? Is the transmitted power the highest when it is in resonance? [Copy link]

 

Is there any relationship between the cutoff frequency and the resonant frequency? Is the transmitted power the highest when it is in resonance?

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A pure number is dimensionless, which does not mean it has no units. For example, an angle is defined as the ratio of the length of an arc to its radius. The ratio of two lengths is, of course, a pure number. But an angle has a unit, the unit being radians. An angle has a dimension of 1, or it has no dimensions.   Details Published on 2019-12-23 14:48
 
 

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For a single LC tank, the output voltage of the LC tank is maximum (or minimum) when the input signal frequency is exactly the resonant frequency. The cutoff frequency refers to the frequency when the output voltage is 0.707 times the maximum (or minimum) value. The cutoff frequency determines the bandwidth of the bandpass (or bandstop) filter.

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It's all about the frequency of the input signal.  Details Published on 2019-12-19 10:35
 
 
 

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The resonant frequency and cutoff frequency of the LC circuit are independent of the input signal and are inherent characteristics of the LC circuit, determined by the inductance, capacitance and equivalent resistance of the LC circuit.

 
 
 

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How to know the maximum gain?

You can measure the inductance, capacitance and equivalent resistance and then calculate them, or you can change the input signal frequency and measure the "maximum gain".

 
 
 

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“Is -3dB expressed in logarithms?”

It is a logarithmic method.

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How are 0.707 and -3DB converted? -3DB=LgX?  Details Published on 2019-12-19 12:10
 
 
 

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maychang posted on 2019-12-19 10:11 For a single LC circuit, the output voltage of the LC resonant circuit is the maximum (or the minimum) when the input signal frequency is exactly the resonant frequency. The cut-off frequency refers to the output voltage...

It's all about the frequency of the input signal.

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"Maximum", "minimum", "-3dB"...are relative to the input signal frequency. However, "resonance frequency" and "cutoff frequency" have nothing to do with the input signal frequency. Without input signal, the resonant frequency is still  Details Published on 2019-12-19 10:52
 
 
 

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QWE4562009 posted on 2019-12-19 10:35 They are all based on the frequency of the input signal

"Maximum", "minimum", "-3dB"... refer to the input signal frequency.

However, the "resonance frequency" and "cut-off frequency" have nothing to do with the input signal frequency. Without input signal, the resonant frequency remains the same value, which is completely determined.

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The cutoff frequency should be related to the input frequency. When it reaches this frequency, the signal will attenuate immediately.  Details Published on 2019-12-19 12:11
 
 
 

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maychang posted on 2019-12-19 10:16 “Is -3dB expressed in logarithms?” It is expressed in logarithms.

How are 0.707 and -3DB converted? -3DB=LgX?

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The definition of "Bel" is the common logarithm of the ratio of two powers, i.e. lg(P2/P1). "Decibel" is abbreviated as "decibel", recorded as dB, and is defined as one tenth of a Bel, i.e. 10lg(P2/P1).  Details Published on 2019-12-23 15:41
The definition of "Bel" is the common logarithm of the ratio of two powers, i.e. lg(P2/P1). "Decibel" is abbreviated as "decibel", recorded as dB, and is defined as one tenth of a Bel, i.e. 10lg(P2/P1).  Details Published on 2019-12-19 12:44
The definition of "Bel" is the common logarithm of the ratio of two powers, i.e. lg(P2/P1). "Decibel" is abbreviated as "decibel", recorded as dB, and is defined as one tenth of a Bel, i.e. 10lg(P2/P1).  Details Published on 2019-12-19 12:41
 
 
 

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maychang posted on 2019-12-19 10:52 “Maximum”, “minimum”, “-3dB”…are for the input signal frequency…

The cutoff frequency should be related to the input frequency. When it reaches this frequency, the signal will attenuate immediately.

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As mentioned before: if there is no input signal, the cutoff frequency remains the same. No matter how the input signal frequency changes (same or different from the resonant frequency, same or different from the cutoff frequency), the cutoff frequency will not change. Therefore, the cutoff frequency has nothing to do with the input signal frequency. The cutoff frequency is determined by the LC filter circuit itself.  Details Published on 2019-12-19 12:49
As mentioned before: if there is no input signal, the cutoff frequency remains the same. No matter how the input signal frequency changes (same or different from the resonant frequency, same or different from the cutoff frequency), the cutoff frequency will not change. Therefore, the cutoff frequency has nothing to do with the input signal frequency. The cutoff frequency is determined by the LC filter circuit itself.  Details Published on 2019-12-19 12:47
 
 
 

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QWE4562009 posted on 2019-12-19 12:10 How is 0.707 and -3DB converted? Is -3DB=LgX?

The definition of "Bell" is the common logarithm of the ratio of two powers, that is, lg(P2/P1).

"Decibel" is abbreviated as "decibel", recorded as dB, and is defined as one tenth of a Bel, that is, 10lg(P2/P1).

 
 
 

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QWE4562009 posted on 2019-12-19 12:10 How is 0.707 and -3DB converted? Is -3DB=LgX?

-3dB, that is, 10lg(P2/P1) = -3, which is lg(P2/P1) = -0.3. From lg(P2/P1) = -0.3, take the antilogarithm and you get P2/P1 = 0.5, that is, P2 = 0.5P1.

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What are P1 and P2 here?  Details Published on 2019-12-23 10:57
What are P1 and P2 here?  Details Published on 2019-12-23 10:46
What are P1 and P2 here?  Details Published on 2019-12-19 14:08
 
 
 

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QWE4562009 posted on 2019-12-19 12:11 The cutoff frequency should be related to the input frequency. When it reaches this frequency, the signal will attenuate immediately

As mentioned before: without input signal, the cutoff frequency remains the same. No matter how the input signal frequency changes (same or different from the resonant frequency, same or different from the cutoff frequency), the cutoff frequency will not change. Therefore, the cutoff frequency has nothing to do with the input signal frequency, and the cutoff frequency is determined by the parameters of the LC filter circuit itself.

 
 
 

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QWE4562009 posted on 2019-12-19 12:11 The cutoff frequency should be related to the input frequency. When it reaches this frequency, the signal will attenuate immediately

"At this frequency, the signal immediately attenuates"

No, the signal attenuation does not happen "instantly" but varies continuously.

 
 
 

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maychang posted on 2019-12-19 12:44 -3dB, that is, 10lg(P2/P1)=-3, which is lg(P2/P1)=-0.3. From lg(P2/P1)=-0.3, find the antilogarithm and get P2/P1=0. ...

What are P1 and P2 here?

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Two power values, such as signal and noise.  Details Published on 2019-12-19 14:42
Two power values, such as signal and noise.  Details Published on 2019-12-19 14:14
 
 
 

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Two power values, such as signal and noise.

 
 
 

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"What are P1 and P2 here?"

Two power values need to be compared, such as output power and input power, or power at a resonant frequency and power at a cutoff frequency.

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Output P2/Input P1, right? Why do some of them show 20lg instead of 10lg?  Details Published on 2019-12-23 10:42
 
 
 

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maychang posted on 2019-12-19 14:42 "What are P1 and P2 here?" Two power values that need to be compared, such as output power and input power, or resonant frequency...

Is it output P2/input P1?

Why do some of them show 20lg instead of 10lg?

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If the comparison is not between two power values, but between two voltage values or two current values (current values are rare), then it becomes 20lg, because power is proportional to the square of voltage (power is also proportional to the square of current).  Details Published on 2019-12-23 11:29
 
 
 

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maychang posted on 2019-12-19 12:44 -3dB, that is, 10lg(P2/P1)=-3, which is lg(P2/P1)=-0.3. From lg(P2/P1)=-0.3, find the antilogarithm and get P2/P1=0. ...

How can we express power in dB when the power is always in W? Isn't it also good to express W in scientific notation? And what parameter is dBm used to express?

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The power unit has disappeared in (P2/P1). I have posted a post discussing elementary functions. The independent variable of a logarithmic function must be a dimensionless pure number, and its result (function value) must also be a dimensionless pure number. Therefore, Bel (or decibel) is dimensionless.  Details Published on 2019-12-23 11:27
 
 
 

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maychang posted on 2019-12-19 12:44 -3dB, that is, 10lg(P2/P1)=-3, which is lg(P2/P1)=-0.3. From lg(P2/P1)=-0.3, find the antilogarithm and get P2/P1=0. ...

Can I use the calculator that comes with my computer to calculate the antivalue? I tried this and it turns out that -0.3 is an invalid input, but 0.3 can be calculated. For example, first enter 0.9321, then press the Inv key, and finally press the ln key or log key. You can get 2.5398372393976584087036045094395 or 8.5526362194046651256482187750074.

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I don't know whether the calculator that comes with your computer can calculate the antilogarithm. However, since your computer can calculate the antilogarithm of a positive number, use a positive number (absolute value) to calculate. The reciprocal of the result of the calculation with a positive number is the result of calculating the antilogarithm with a negative number. For example, the antilogarithm of 0.30103 is 2, -0.30103  Details Published on 2019-12-23 11:34
 
 
 

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QWE4562009 posted on 2019-12-23 10:46 How can we express power in DB when the power is in W? Isn't it also good to express W in scientific notation? And what parameter is dBm used to express?

The power unit has disappeared in (P2/P1).

I have posted a post discussing elementary functions. The independent variable of a logarithmic function must be a dimensionless pure number, and its result (function value) must also be a dimensionless pure number. Therefore, Bel (or decibel) is dimensionless.

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What does a dimensionless pure number mean? No units?  Details Published on 2019-12-23 14:42
 
 
 

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