The fourth example of one hundred examples of C language

Code:

/*

The fourth example of C language

Question: Enter a certain year, a certain month and a certain day, and determine what day of the year this day is?

Program analysis: Taking March 5th as an example, you should first add up the previous two months, and then add 5 days, which is the day of the year. In special circumstances, if it is a leap year and the input month is greater than 3, you need to consider adding an extra day. .

*/

#include

void main(void)

{

    int year,month,day,sum,temp;

    printf("Please enter date, month, day: n");

    scanf("%d,%d,%d",&year,&month,&day);

    switch(month) //Assuming it is March, add the number of days in the previous two months and add the number of days in this month.

    {

        case 1:sum=0;break;

        case 2:sum=31;break;

        case 3:sum=59;break;

        case 4:sum=90;break;

        case 5:sum=120;break;

        case 6:sum=151;break;

        case 7:sum=181;break;

        case 8:sum=212;break;

        case 9:sum=243;break;

        case 10:sum=273;break;

        case 11:sum=304;break;

        case 12:sum=334;break;

    }

    sum=sum+day;

    if(year%400==0||(year%4==0&&year%100!=0)) //Determine whether it is a leap month. For leap months, add one day to this basis.

    {

        temp=1;

    }

    else

    {

        temp=0;

    }

    if(temp==1&&month>2)

    {

        sum++;

    }

    printf("%d, %d, %d, is the %d day n", year, month, day, sum);

}

operation result: