Classic C Program (13/20)-EEWORLD

Collect

Title: Output an array in reverse order.
1. Program analysis: Swap the first with the last.
2. Program source code:
#define N 5
main()
{ int a[N]={9,6,5,4,1},i,temp;
　printf(" original array: ");
　for(i=0;i 　printf("%4d",a[i]);
　for(i=0;i 　{temp=a[i];
　　a[i]=a[Ni-1];
　　a[Ni-1]=temp;
　}
printf(" sorted array: ");
for(i=0;i 　printf("%4d",a[i]);
}

Title: There is an array that has been sorted. Now enter a number and insert it into the array according to the original rule.
1. Program analysis: First determine whether this number is greater than the last number, then consider the situation of inserting the middle number. After the insertion,
　　　　　the numbers after this element will be moved back one position in turn.
2. Program source code:
main()
{
int a[11]={1,4,6,9,13,16,19,28,40,100};
int temp1,temp2,number,end,i,j; 　printf(
"original array is: "); for (
i=0;i< 　10;i++) printf 　　( "%5d",a[i]); printf(" " 　) 　　　　; 　　　printf 　　　( 　　　" 　　　　insert 　　a new 　　　number 　　　　; 　　　} } 　　　} for(i=0;i<11;i++) 　printf("%6d",a[i]); }

Title: Find the sum of the diagonal elements of a 3*3 matrix
1. Program analysis: Use a double for loop to control the input of a two-dimensional array, and then add a[i][i] and output it.
2. Program source code:
main()
{
float a[3][3],sum=0;
int i,j;
printf("please input rectangle element: ");
for(i=0;i<3;i++)
　for(j=0;j<3;j++)
　scanf("%f",&a[i][j]);
for(i=0;i<3;i++)
　sum=sum+a[i][i];
printf("duijiaoxian he is %6.2f",sum);
}

Title: Sort 10 numbers
1. Program analysis: You can use the selection method, that is, from the last 9 comparisons, select a smallest one and exchange it with the first element, and
　　　　　　then repeat the same process, that is, compare the second element with the last 8 and exchange them. 　　　　　　
2. Program source code:
#define N 10
main()
{int i,j,min,tem,a[N];
/*input data*/
printf("please input ten num: ");
for(i=0;i {
printf("a[%d]=",i);
scanf("%d",&a[i]);}
printf(" ");
for(i=0;i printf("% 5d",a[i]);
printf(" ");
/*sort ten num*/
for(i=0;i {min=i;
for(j=i+1;j if(a[min]>a[j]) min=j;
tem=a[i];
a[i]=a[min];
a[min]=tem;
}
/*output data*/
printf("After sorted ");
i=0;i printf("%5d",a[i]);
}

题目：求100之内的素数　　　
1.程序分析：
2.程序源代码：
＃i nclude
＃i nclude "math.h"
#define N 101
main()
{
int i,j,line,a[N];
for(i=2;i for(i=2;i 　for(j=i+1;j 　{
　　if(a[i]!=0&&a[j]!=0)
　　if(a[j]%a[i]==0)
　　a[j]=0;}
printf(" ");
for(i=2,line=0;i {
　if(a[i]!=0)
　{printf("%5d",a[i]);
　line++;}
　if(line==10)
　{printf(" ");
line=0;}
}
}

Reference address：Classic C Program (13/20)

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