1. Sudden increase in power supply voltage. There are many reasons for the sudden increase in power supply voltage, such as power quality problems or improper use by users.
2. A short circuit of a component, printed line or other wire in the circuit forms a local short circuit in the LED power supply path, causing the voltage in this place to increase.
3. If an LED is damaged due to its own quality reasons and forms a short circuit, its original voltage drop will be transferred to other LEDs.
4. The temperature inside the lamp is too high, causing the characteristics of the LED to deteriorate.
5. Water has entered the lamp, and water is conductive.
6. When assembling, the anti-static work is not done well, so that the internal part of the LED has been damaged by static electricity. Even if the voltage and current are normal, it is very easy to damage the LED.
All these reasons will cause the LED current to rise significantly, and soon the LED chip will be burned due to overheating. According to our experience, most LEDs burn out due to short circuits between the two poles, and a few are open circuits. Each LED has a voltage drop of about 3.2V. If it burns out and the circuit is open, the string of LEDs will not emit light. If it is short-circuited, the voltage will be transferred to other LEDs, causing a larger current in other LEDs, and other LEDs will be burned out faster, or even endanger the power supply. A small damage can easily cause a big accident. LEDs are usually installed at high places, which is not easy to install, and even more difficult to repair. Therefore, the protection of LEDs is a practical need, but it is not taken seriously by everyone at present, and it is also a problem that many people are helpless and have no way to deal with.
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Recommended ReadingLatest update time:2024-11-16 21:55
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