Double button light switch circuit (12)

It is a double-touch mode light switch made of CD1013 digital integrated circuit, with
good operating performance. CD4013 is a
double D flip-flop. This
circuit only uses one of the
I) flip-flops and
connects it to an RS flip-flop.
C. , R, form a differential circuit
, so that
when the circuit is powered on for the first time, a stop
pulse is generated and added to the R terminal of CD4013
, which is the ④ pin, forcing
the circuit to reset, and the Q terminal, which is the ① pin, outputs low level , VT3, VT-1 All are turned off, and the light E does not light up.
    When you need to turn on the light, just touch the -Bu electrode piece Ml, and the human body leakage current passes through R. Injecting the base of VT1,
its negative half cycle turns Wfl on. Therefore, the S terminal of Cn4013, that is, the ⑥ pin, is set by the positive pulse circuit, the Q
terminal outputs high level, VT3 is turned on, the thyristor VTH is turned on, and the lamp E is powered on and emits light. After the human hand leaves M1
, the circuit status remains unchanged. When turning off the light, as long as the human hand touches M2, VT2 is turned on, that is,
a stop pulse is input to the ruler end of CD4013, the circuit flips and resets, the Q end jumps to low level , and the lamp E goes out. The circuit
returns to its original state.
    VT1 and VT2 are 9012-type silicon PNP diode tubes, VT3 is a 9013-type NI, N_pole tube, and the p value
is less than 100. VTH can be chipped j1A/,IOOV small plastic-encapsulated thyristor, such as MAC9-1A4 type, etc. (1.
It is required to use ff CBB 4. V-type acrylic capacitor. See the figure for other component parameters. There are no special requirements.