This article comprehensively introduces the selection and design of servo motors

Overview of Servo Motor Selection and Design

Servo drives and motors are matched to the performance of industrial machines: inertia, capacity and speed.

Inertia: For general mechanisms, JL ≤ JM. When JL ≥ 3JM, controllability will decrease. Different mechanisms have different requirements for inertia matching.

Capacity - Determined according to the motor load, the rated torque of the motor is required to match the load of the driven mechanical system. Usually TM x 0.8 > TL. The Buke motor can achieve 3 times overload and there is no need to reserve capacity.

Speed: Reducer. Low speed and high torque operation

Servo motor selection considerations: mechanical load, action mode, load speed, positioning accuracy, and operating environment.

This article comprehensively introduces the selection and design of servo motors

Note: Taking Exercise 3 as an example, the selection and design steps are as follows:

According to the calculation formula of the cylinder inertia

JL=0.5M R2 =0.5x10x0.12=0.05kg.m2

Calculate the angular acceleration θ:

θ=(2Π) x300/(60x1)=31.4rad/s2

Ts=(JL+JM) xθ =(0.05+JM)x31.4 = 1.57+31.4JM

Ts - starting torque

Required torque:

T = S x Ts (overcoming air resistance is ignored here)

S＝2, we get: T=3.14+62.8JM>3.14Nm

Take the motor with the largest inertia, inertia JM = 1.1x10-3 kg.m2, JL/JM = 46

Considering that the inertia ratio is much larger than the ideal range of 3-5, the system is not suitable for direct drive. You can consider increasing the inertia ratio by deceleration, and this should also be taken into account when selecting the system.