Require:
The light is off when the power is on. Press the button once and the light will turn on. Press it again and the light will flash. Press it again and the light will flash faster.
Press again and the light turns off...
The cycle continues.
To do this, program as follows.
//----------------------------------------------
#include
unsigned char n = 0;
sbit key = P3^4;
sbit led = P0^0;
void delay()
{
unsigned int i, j;
for(i = 0; i < 100; i++) for(j = 0; j < 500; j++);
}
void readkey(void)
{
unsigned char i, j;
if(!key) {
for(i = 0; i < 10; i++)
for(j = 0; j < 120; j++); //delay debounce
if(!key) {
while(!key); //Wait for the key to be released
n++;
n %= 4; //n = 0~3
}
}
}
main()
{
while(1) {
switch(n) {
case 0: led = 1; readkey(); break; //turn off
case 1: led = 0; readkey(); break; //长亮
case 2: delay(); readkey(); //slow flashing
case 3: delay(); readkey(); led = ~led; //fast flashing
}
}
}
//----------------------------------------------
This program has been verified in practice and can meet the requirements of the topic.
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