Newbie seeking guidance, about msp430led water lamp code problem

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Newbie seeking guidance, about msp430led water lamp code problem [Copy link]

Function name: Timer_A Function: Interrupt service function of timer A, where the flow direction and flow speed of the water lamp are controlled by the flag Parameter: None Return value: None **********************************************/ #pragma vector = TIMERA0_VECTOR __interrupt void Timer_A (void) { if(flag == 0) { P2OUT = ~(0x80>>(i++)); //The lighting order of the lamp is D8 -> D1 } else if(flag == 1) { P2OUT = ~(0x01<<(i++)); //The lighting order of the lamp is D1 -> D8 } else { if(dir) //The lighting order of the lamp is D8 -> D1, D1 -> D8, looping around { P2OUT = ~(0x80>>(i++)); } else { P2OUT = ~(0x01<<(i++)); } } ...... The following code is omitted. What I want to ask is if(flag == 0) { P2OUT = ~(0x80>>(i++)); //The order of lights turning on D8 -> D1 }. In this paragraph, when flag=0, i++=0, D8 is on. There is no for statement loop for i here. Why does the comment say that D8-D1 will turn on in sequence?

qwerghf

Because the interrupt will always enter, it is equivalent to a for loop

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qwerghf posted on 2018-7-18 08:12 Because the interrupt will always enter, it is equivalent to a for loop

Yes, thank you.