The OP
Published on 2018-1-13 21:25
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This post is from Analog electronics
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Understand the operation. The 20V at the virtual short same-direction input end is divided by two resistors to get 11.05V. The virtual short reverse input is also 11.05V. The voltage difference between the two ends of the reverse input end is 1.05V. The resistor is 100 ohms and the current at the reverse input end is 10.05ma. There is no problem.
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Published on 2018-1-15 18:57
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Published on 2018-1-13 22:07
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Published on 2018-1-13 22:17
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Published on 2018-1-14 16:57
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This post is from Analog electronics
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Using the circuit formula directly, we can indeed get an output voltage of 16.3V, but at the same time, we can also get a voltage of 11.05V at the two input terminals of the op amp. It is this tiny 50mV error that makes the simulation result appear to be inconsistent with Ohm's law.
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Published on 2018-1-15 08:31
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Published on 2018-1-15 08:31
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