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tongshaoqiang
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Published on 2024-10-16 19:06
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Use 24V voltage to directly power the G pole. If the voltage is too high, it should be reduced to about 12V. Connect a 0.25A fuse resistor or fuse in series in the middle. When the MOS tube burns out, the fuse burns out, and the 24V power supply is disconnected.
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Published on 2024-10-18 11:14
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Published on 2024-10-16 20:06
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Disposable lithium battery
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Published on 2024-10-17 07:57
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qwqwqw2088
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Published on 2024-10-17 07:50
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qwqwqw2088
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Published on 2024-10-17 07:50
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Thanks for knowing! The short circuit of the input and output of BL8307 will cause a 24V high voltage at the drain of MOS2. If the DS of mos3 can withstand this high voltage and does not cause the DS of MOS3 to break down and short-circuit, the battery will not be charged at a high voltage, right?
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Published on 2024-10-17 14:01
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tongshaoqiang
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It is not suitable to design the circuit like this for disposable lithium batteries. It is OK to directly connect the positive output of the battery to a Schottky diode to prevent reverse current. What kind of MOS should be used? The current is particularly large? ? ?
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Published on 2024-10-17 10:10
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chineseboyzxy
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Published on 2024-10-17 08:33
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Published on 2024-10-17 08:53
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No, when the external input power supply is connected, the gate of MOS3 is about 8V, the S pole is 3.62V, and Pmos is turned off.
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Published on 2024-10-17 14:10
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Published on 2024-10-17 10:10
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The current is not very large. In 4G communication, there will be a very short-term peak current of 1A, and a longer period of time is 300mA.
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Published on 2024-10-17 14:12
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tongshaoqiang
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tongshaoqiang
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tongshaoqiang
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tongshaoqiang
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MOS tube is damaged, often GS short circuit, three motors short circuit is also common. If MOS3 GD short circuit, then obviously VDD_24 24V voltage will charge the battery at VCC_BAT. However, the current is not large, because of R3, the current will not exceed 2mA.
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Published on 2024-10-17 15:07
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Published on 2024-10-17 15:07
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Thanks for the reply! If both MOS2 and MOS3 have GDS short circuit, there will be a large current to charge the battery at VCC_BAT, so the battery will explode, right? But there is a chance that both MOS2 and MOS3 have GDS short circuit, but it will not be too high, right? In this way, does every circuit have a possibility of being unusable?
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Published on 2024-10-17 15:37
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tongshaoqiang
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It is not necessary for both MOS2 and MOS3 to be damaged. As long as the GD of MOS3 is short-circuited, 24V will charge the battery at VCC_BAT. I feel that MOS tube damage is more likely to occur during the welding assembly process. After being installed in the whole machine, as long as the design is correct, the probability of damage is not high.
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Published on 2024-10-17 15:52
It is not necessary for both MOS2 and MOS3 to be damaged. As long as the GD of MOS3 is short-circuited, 24V will charge the battery at VCC_BAT. I feel that MOS tube damage is more likely to occur during the welding assembly process. After being installed in the whole machine, as long as the design is correct, the probability of damage is not high.
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Published on 2024-10-17 15:49
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Published on 2024-10-17 15:49
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Published on 2024-10-17 15:52
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Published on 2024-10-18 10:10
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Published on 2024-10-18 11:14
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