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This post was last edited by maychang on 2018-6-26 11:29 okhxyyo seems to like to post brain teasers. Now I will post one on behalf of okhxyyo: How to represent three decimal numbers without using operators as the largest integer? Three 1s: 1 times 1 is still 1, and 1 to the power of 1 is still 1. Obviously, the largest integer that can be formed by three 1s without using operators is Three 9s: The largest integer that can be formed by three 9s is not . In fact, the largest integer that can be formed by two 9s without using any arithmetic operators is 360837, which is 387420489 in decimal, much larger than 999. Three 9s can be expressed as 360839, which is a 95-digit decimal number. Three 9s can be expressed as 360840, which is an incredibly large integer. Here comes the question: @okhxyyo(1) How many digits does 360849 have when written as a decimal number? (2) How to express three numbers 2, three numbers 3, three numbers 4, etc. as the largest integer without using any operation symbols? Adapted from "Fun Algebra" by Barry Lehrman

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It is actually not difficult to answer such questions as long as you have a spirit of questioning and empiricism, and questioning and empiricism are the foundation of science.  Details Published on 2018-6-26 16:06
 
 

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1. Is it an 81-digit number? 2. 222 is the largest, 3 ((3)3), 4 is the same, that is, after 3, it is exponential, and the data is the largest.
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22 to the power of 2 is 484, and 2 to the power of 22 is 4194304, both of which are larger than 222. 3 to the power of 3 is 27, and 3 to the power of 33 is obviously larger than 3 to the power of 27.  Details Published on 2018-6-26 12:01
 
 
 

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star_66666 posted on 2018-6-26 11:37 1. Is it an 81-digit number? 2. 222 is the largest, and so is 3 ((3)3). The same is true for 4, which means that after 3, the data is the largest in exponential form.
22 to the power of 2 is 484, and 2 to the power of 22 is 4194304, both of which are larger than 222. 3 to the power of 3 is 27, and 3 to the power of 33 is obviously larger than 3 to the power of 27.
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9 to the power of 9 is a 9-digit number, which is very interesting. The first digit is 987654321.9 to the power of 9, which is 81 digits.
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9 to the 9th power of 9 is 81 digits. No way? [attachimg]360882[/attachimg], written in decimal is 387420489. [attachimg]360883[/attachimg] is a 95-digit decimal number. [attachimg]360884[/attachimg] written in decimal  Details Published on 2018-6-26 12:47
 
 
 

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There are still many tall people.
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This post was last edited by maychang on 2018-6-26 12:49
okhxyyo posted on 2018-6-26 12:16 9 to the power of 9 is 9 digits, very interesting, the first digit is 987654321.9 to the power of 9, 81 digits.
9 to the power of 9, 81 digits. No way? , written in decimal, is 387420489. , is a 95-digit decimal number. , written in decimal, can only have more digits than 95, not 81. is 9 raised to the power of 387420489.
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⊙⊙! Let me think about it calmly  Details Published on 2018-6-26 12:51
 
 
 

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maychang posted on 2018-6-26 12:47 9 to the 9th power of 9 is 81 digits. No way? , written in decimal form is 387420489. , is a 95-digit decimal number...
⊙⊙! Let me think about it calmly
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Let me think about this calmly. Hint: Take the logarithm of 9 raised to the power of 387420489 (any base).  Details Published on 2018-6-26 12:53
 
 
 

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okhxyyo posted on 2018-6-26 12:51 ⊙⊙! Let me think about it calmly
Let me think about it calmly Hint: Take the logarithm of 9 to the power of 387420489 (any base).
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okhxyyo posted on 2018-6-26 12:53 I didn't calculate, and didn't count the carry at the end, 囧囧囧, but what does 95 decimal mean, isn't this a 9-digit number?
But what does 95 decimal mean, isn't this a 9-digit number? is equal to 2.951266543 multiplied by 10 to the 94th power, which is a 95-digit decimal number.
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Is this a cramp question? I got cramps right after I finished the calculation!
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1. Take the common logarithm, which should be (9^9 * lg9 + 1) decimal digits (369, 693, 100 digits?) 2. 2^22, 3^33 are the largest, and the rest are 4^(4^4) which is the largest. .
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Yes. More than 300 million.  Details Published on 2018-6-26 15:06
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wsmysyn posted on 2018-6-26 14:33 1. Taking the common logarithm, it should be (9^9 * lg9 + 1) so many decimal digits (369,693,100 so many digits?) 2. 2^22, 3^33 is the most...
Indeed. More than 300 million digits.
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Seeing this number, although it is written simply, the number of digits is more than 300 million, and then I thought of the Graham number.  Details Published on 2018-6-26 15:21
 
 
 

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maychang posted on 2018-6-26 15:06 Indeed. More than 300 million digits.
When I saw this number, although it was written in a simple way, the number of digits was already more than 300 million, and then I thought of the Ge Liheng number
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Compared with the Graham number, this number of more than 300 million digits is just zero, just 9^9^9.  Details Published on 2018-6-26 15:43
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wsmysyn posted on 2018-6-26 15:21 When I saw this number, although it is written in a simple way, the number of digits is more than 300 million, and then I thought of the Graham number
Compared with the Graham number, this more than 300 million digits is just zero, just 9^9^9.
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Yes, yes... It seems that there are known meaningful numbers that are much, much larger than the Graham number... It's already a headache to understand...  Details Published on 2018-6-26 15:53
 
 
 

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maychang posted on 2018-6-26 15:43 Compared with the Graham number, this 300 million digits is just a zero, 9^9^9.
Yes, yes... It seems that there are known meaningful numbers that are much larger than the Graham number... It's already a headache to understand it.
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It is actually not difficult to answer such questions as long as you have a spirit of questioning and empiricism, and questioning and empiricism are the foundation of science.
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