【Theme Month】Please analyze the bridge full-wave rectifier circuit. If the diodes in the circuit have the following conditions, what will happen?

tiankai001

【Theme Month】Please analyze the bridge full-wave rectifier circuit. If the diodes in the circuit have the following conditions, what will happen? [Copy link]

The figure below shows a bridge full-wave rectifier circuit. If the following situations occur in the diodes in the circuit, what problems will occur respectively? 1. D1 is open circuit; 2. D2 is short circuit; 3. D3 polarity is reversed; 4. D1 and D2 polarities are both reversed; 5. D1 is open circuit and D2 is short circuit. The answer is here (visible in the reply)

1. Full-wave rectification becomes half-wave rectification 2. D1 and the secondary winding of the transformer may be burned 3. During the positive half cycle of U2, D3, D4 and the secondary winding may be burned due to overcurrent 4. The normal rectification current path is cut off, and there is no output waveform on RL. Full-wave rectification becomes half-wave rectification. During the positive half cycle of U2, there is a rectified waveform on RL

fxyc87

1, turn to half wave 2 burn-in 3 burn-in 4 open circuit, no response 5 half wave

xujian2000

1. It becomes half-wave rectifier output. 2. It causes the fuse to burn out (there is no fuse in the picture, but it will penetrate into the power input terminal in actual application). 3. It causes the fuse to burn out (there is no fuse in the picture, but it will penetrate into the power input terminal in actual application). 4. There is no DC current output. 5. It becomes half-wave rectifier output.

皈依

Same as above

周振宇

I don't really understand

hk6108

Let’s talk about one tube first. If one tube is open, it becomes a half-wave rectifier. If one tube breaks down, the tube in the same position (DC potential) will burn out.

hk6108

As long as one tube is short-circuited, the rectifier bridge will be burned beyond recognition even if it does not explode. If two tubes are open-circuited, the diagonal tube will become a half-wave rectification of two tubes in series. If the AC isotropic tube is open-circuited, the entire bridge will be blocked and the circuit will be interrupted.