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This post was last edited by Chen Huixing on 2023-3-6 16:45



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Is there a temporary load? How big is it?   Details Published on 2023-3-8 09:25
 
 

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If you want to get a quick and accurate reply, you should first explain which point in the figure above the waveform is, and clearly mark the components in the figure above, using standard symbols. What are the three pins marked A1, V1, etc. in the figure above? What are the signals input to the four IGBTs?

 
 
 

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[I want to output 10KV]

10kV, AC or DC? From the electrical schematic, the output is voltage doubler, so the 10kV you want should be DC. But if the output you want is DC, why use an oscilloscope to see the waveform?

 
 
 

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In addition, 10kV voltage is no joke. Can your oscilloscope probe withstand 10kV voltage?

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It is just a simulation without considering the reality. The output is the waveform of the voltage doubler rectifier circuit. The four IGBT inputs are square wave signals with a frequency of 20KV.  Details Published on 2023-3-5 16:15
 
 
 

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maychang posted on 2023-3-5 13:38 In addition, 10kV voltage is no joke. Can your oscilloscope probe withstand 10kV voltage?

It is just a simulation without considering the reality. The output is the waveform of the voltage doubler rectifier circuit. The four IGBT inputs are square wave signals with a frequency of 20KHZ.

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[It is just a simulation without considering reality, and the output is the waveform of the voltage doubler rectifier circuit] There are two waveforms in the first post: the upper one is the output of the voltage doubler rectifier, which is a DC voltage that rises relatively slowly, and what is the waveform below? Or to be more precise, at which point in the circuit is the waveform?  Details Published on 2023-3-5 17:49
[It is just a simulation without considering reality, and the output is the waveform of the voltage doubler rectifier circuit] There are two waveforms in the first post: the upper one is the output of the voltage doubler rectifier, which is a DC voltage that rises relatively slowly, and what is the waveform below? Or to be more precise, at which point in the circuit is the waveform?  Details Published on 2023-3-5 17:42
[It is just a simulation without considering reality, and the output is the waveform of the voltage doubler rectifier circuit] There are two waveforms in the first post: the upper one is the output of the voltage doubler rectifier, which is a DC voltage that rises relatively slowly, and what is the waveform below? Or to be more precise, at which point in the circuit is the waveform?  Details Published on 2023-3-5 17:40
 
 
 

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Morning Star published on 2023-3-5 16:15 It is just a simulation without considering the reality. The output is the waveform of the voltage doubler rectifier circuit. The four IGBT inputs are square wave signals with a frequency of 20KHZ

[It is just a simulation without considering the reality, and the output is the waveform of the voltage doubler rectifier circuit]

There are two waveforms in the first post: the top one is the voltage doubler rectifier output, which is a DC voltage that rises relatively slowly, and what is the waveform below? Or to be more precise, at which point in the circuit is the waveform?

 
 
 

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Morning Star published on 2023-3-5 16:15 It is just a simulation without considering the reality. The output is the waveform of the voltage doubler rectifier circuit. The four IGBT inputs are square wave signals with a frequency of 20KHZ

[The four IGBT inputs are square wave signals with a frequency of 20KHZ]

The input signals of these four IGBTs cannot be simple square waves. The signals of the two tubes on the diagonal must be complementary to the signals of the two tubes on the other diagonal, and a "dead zone" must be left.

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Morning Star published on 2023-3-5 16:15 It is just a simulation without considering the reality. The output is the waveform of the voltage doubler rectifier circuit. The four IGBT inputs are square wave signals with a frequency of 20KHZ

[It’s just a simulation without considering reality]

After the industrial frequency AC rectification and filtering, you used an IGBT tube and L2C2D6 to form a Buck circuit. What is your intention?

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Control the BUCK circuit to achieve voltage regulation through PWM signal   Details Published on 2023-3-5 18:17
 
 
 

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maychang posted on 2023-3-5 17:49 [It is just a simulation without considering the reality] You used an IGBT tube after the industrial frequency AC rectification and filtering, and formed a Buck circuit with L2C2D6. What is this...

Control the BUCK circuit to achieve voltage regulation through PWM signal

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[Voltage regulation is achieved by controlling the BUCK circuit through PWM signal] So the title saying "I want to output 10KV" is incomplete, and it should be added with "adjustable, maximum 10kV".  Details Published on 2023-3-5 18:49
[Voltage regulation is achieved by controlling the BUCK circuit through PWM signal] So the title saying "I want to output 10KV" is incomplete, and it should be added with "adjustable, maximum 10kV".  Details Published on 2023-3-5 18:45
 
 
 

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Morning Star published on 2023-3-5 18:17 Voltage regulation is achieved by controlling the BUCK circuit through PWM signal

【Control the BUCK circuit through PWM signal to achieve voltage regulation】

So the title saying "I want to output 10KV" is incomplete, it should be added "adjustable, maximum 10kV".

 
 
 

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Morning Star published on 2023-3-5 18:17 Voltage regulation is achieved by controlling the BUCK circuit through PWM signal

I once said: "10kV is not a joke." If you use quadruple voltage rectification, the secondary of the transformer driven by the four IGBTs requires at least 2500V peak. The transformer turns ratio must be at least 1:10, and the winding method is quite particular. Of course, the simulation does not take the winding method into account.

 
 
 

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This post was last edited by Chen Huixing on 2023-3-5 20:00

Hi, the first picture shows the voltage and current waveforms of the voltage doubler circuit after operation. The second picture shows the output waveforms of the rectifier, buck circuit, inverter circuit, and transformer. The third picture shows the output waveforms of the rectifier, buck circuit, inverter circuit, and transformer after removing the voltage doubler rectifier circuit. Why does the first picture appear after the complete circuit is operated? Is there a solution?


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[Is there a solution? ] What problem do you want to solve? The title of the first post says "Why is the output waveform like this?" and also says "I want to output 10kV." What do you want to solve? Solve the output waveform or still output less than 10kV?  Details Published on 2023-3-6 10:24
[Is there a solution? ] What problem do you want to solve? The title of the first post says "Why is the output waveform like this?" and also says "I want to output 10kV." What do you want to solve? Solve the output waveform or still output less than 10kV?  Details Published on 2023-3-6 10:20
 
 
 

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Morning Star published on 2023-3-5 19:56 Boss, the first picture is the voltage and current waveform output by the voltage doubler circuit after operation, and the second picture is the output waveform of the rectifier, BUCK circuit, inverter circuit, and transformer...

【Is there a solution? 】

What problem does it solve?

The title of the first post says "Why is the output waveform like this?" and then says "I want to output 10kV." What do you want to solve? Solve the output waveform or still output less than 10kV?

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Solve the output waveform or the output is less than 10kV?  Details Published on 2023-3-6 10:43
 
 
 

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Morning Star published on 2023-3-5 19:56 Boss, the first picture is the voltage and current waveform output by the voltage doubler circuit after operation, and the second picture is the output waveform of the rectifier, BUCK circuit, inverter circuit, and transformer...

In the first picture, you said the top one is the output voltage waveform and the bottom one is the current waveform. The symbols of the components in your schematic are very inconsistent with the general symbols. From the schematic, I guess that the waveform below is the current waveform in the rightmost rectifier. If my guess is correct, then the simulation waveform is completely normal and there is no problem.

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The bottom picture is the output waveform of the voltage doubler circuit, rectifier circuit, buck circuit, inverter circuit, and transformer without connecting the voltage doubler circuit. The top picture is the output waveform of the voltage doubler circuit after connecting the voltage doubler circuit. The middle picture is the output waveform of the rectifier circuit, buck circuit, inverter circuit, and transformer after connecting the voltage doubler circuit.  Details Published on 2023-3-6 10:49
 
 
 

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maychang posted on 2023-3-6 10:20 [Is there a solution? ] What problem does it solve? The title of the first post says "Why is the output waveform like this?" and also says "...

The output waveform is still less than 10kV

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[Solving the output waveform or output less than 10kV] What problem do we want to solve?  Details Published on 2023-3-6 10:58
 
 
 

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maychang posted on 2023-3-6 10:24 In the first post, you said that the top is the output voltage waveform and the bottom is the current waveform. The symbols of the components in your electrical schematic are very inconsistent with the general symbols. I...

The bottom picture is the output waveform of the voltage doubler circuit, rectifier circuit, buck circuit, inverter circuit, and transformer without connecting the voltage doubler circuit. The top picture is the output waveform of the voltage doubler circuit after connecting the voltage doubler circuit. The middle picture is the output waveform of the rectifier circuit, buck circuit, inverter circuit, and transformer after connecting the voltage doubler circuit.

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[The bottom picture is the output waveform without connecting the voltage doubler circuit, rectifier circuit, buck circuit, inverter circuit, and transformer] Nothing is connected, where does this waveform come from? At which point in the measurement circuit does the waveform come from?  Details Published on 2023-3-6 10:59
 
 
 

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This post was last edited by Chen Huixing on 2023-3-6 16:46

The capacitor of the voltage doubler circuit is set to 5e-5F, the transformer T1 is 11:1, and the transformer T2 is 1:250

 
 
 

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Morning Star published on 2023-3-6 10:43 Solve the problem that the output waveform is still less than 10kV

[Solving the problem of output waveform or output less than 10kV]

What problem do we want to solve?

 
 
 

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[quote]Morning Star published on 2023-3-6 10:49 The bottom picture is the output waveform of the voltage doubler rectifier circuit, rectifier circuit, BUCK circuit, inverter circuit, and transformer without connection. The top picture is the output waveform of the voltage doubler rectifier circuit, rectifier circuit, BUCK circuit, inverter circuit, and transformer without connection. The top picture is the output waveform of the voltage doubler rectifier circuit, rectifier circuit, BUCK circuit, inverter circuit, and transformer with ...

[The bottom picture is the output waveform of the voltage doubler rectifier circuit, rectifier circuit, BUCK circuit, inverter circuit, and transformer without being connected]

Where does this waveform come from when nothing is connected? At what point in the measurement circuit does the waveform come from?

 
 
 

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Did you delete the topic after the problem was solved? Or did you accidentally click on the wrong button, leaving those who read the post confused?

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Deleted  Details Published on 2023-3-8 16:56
Personal signature虾扯蛋,蛋扯虾,虾扯蛋扯虾
 
 
 

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