Porter-3: Will this topology work?

不亦心

Porter-3: Will this topology work? [Copy link]

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I saw a new topology, but I don’t quite understand how it works. Let’s discuss it.

maychang

From the figure, it seems that switches S1 and S2 are closed and opened alternately and work complementarily.

When switch S2 is closed, the inductor L1 can indeed be "charged" through the capacitor C2 and the load RL. However, after the switch S2 is closed, it must be opened. Where should the energy stored in L1 be released after it is opened?

chineseboyzxy

S1/S2 are turned on complementary. When S1 is turned on and S2 is turned off, the current flows through S1, C1, D2, L2, and RL to the negative electrode; when C1 is fully charged, the left side is positive and the right side is negative, and the current is 0; then S1 is turned off, S2 is turned on, C1 is discharged, and the current flows through S2, L1, RL, and D1 to the other end of C1.

不亦心

maychang posted on 2019-12-1 14:59 From the figure, it seems that switches S1 and S2 are alternately closed and opened, working in a complementary manner. When switch S2 is closed, it can indeed connect the capacitor C2 and the load RL to the inductor L1 ...

Yes, I just don't understand it. I suspect I was fooled by the foreign pictures.

不亦心

chineseboyzxy Published on 2019-12-2 08:45 S1/S2 are complementary. When S1 is on and S2 is off, the current flows through S1, C1, D2, L2, and RL to the negative pole; when C1 is fully charged, the left side is positive and the right side is negative, and the current is 0; then S1 ...

How to continue current when S2 is disconnected

chineseboyzxy

Bu Yixin posted on 2019-12-2 19:28 How to continue current when S2 is disconnected

When S2 is disconnected, capacitor C1 is completely discharged and L1 is suspended. What current is there to continue? Moreover, when S2 is disconnected, S1 is turned on and continues to charge C1, entering the next cycle. This cycle is maintained by the charging and discharging of C1.