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dreamandactual
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Published on 2019-3-2 18:42
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Is it solved?
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Published on 2022-8-3 16:23
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Published on 2019-3-3 09:22
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dreamandactual
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Published on 2019-3-3 10:02
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dreamandactual
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1. The waveform you see is not a 1MHz modulated signal, but a 600MHz modulated wave. From the third picture, the frequency of the 600MHz signal does not change, so your waveform should be an AM wave, and the amplitude of the AM wave should change. 2. If a 1MHz signal modulates a 600MHz carrier, then the modulated wave
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Published on 2019-3-4 14:45
1. The waveform you see is not a 1MHz modulated signal, but a 600MHz modulated wave. From the third picture, the frequency of the 600MHz signal does not change, so your waveform should be an AM wave, and the amplitude of the AM wave should change. 2. If a 1MHz signal modulates a 600MHz carrier, then the modulated wave
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Published on 2019-3-4 13:36
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Published on 2019-3-4 13:36
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Published on 2019-3-4 14:45
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Yes, the oscilloscope frequency is indeed correct, 600Mhz, which is transmitted through AD9361. Because my purpose is to generate a sine wave myself, and then generate 2.4ghz through AD9361 and transmit it. Because my oscilloscope can only test 1g, so I chose 600mhz.
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Published on 2019-3-4 15:23
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dreamandactual
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dreamandactual
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Published on 2019-3-4 20:53
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Published on 2019-3-4 20:57
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Well, I tried not to use DDS output, but if I don't use DDS output, there will be no waveform output. Then for the port, I used differential LVDS and used several fixed ports on the official website. I am a little suspicious whether the output itself should be like this, because my DDS1mhz is used as the modulation signal, and then my carrier
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Published on 2019-3-5 15:23
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dreamandactual
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This post is from Analog electronics
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Wrong. Not using DDS output does not mean that the modulation signal is 0. The port originally connected to the DDS output should be connected to a DC signal (if it is a differential signal, it should be connected to a DC signal with equal positive and negative voltages). You should be able to see a 600MHz equal-amplitude oscillation output.
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Published on 2019-3-6 14:08
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Published on 2019-3-6 14:08
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Yes, it is a differential signal. I directly send it to the DDS port 12'h3f, but I can't see any waveform on the oscilloscope. If it is a DC with equal positive and negative, how should I give it? The data is 12 bits, and the differential is 1 to 6 bits.
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Published on 2019-3-6 17:20
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dreamandactual
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This post is from Analog electronics
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In order to avoid giving wrong instructions due to unfamiliarity with the chip, the most direct and crude way is to disconnect the connection between DDS and AD9361, and then directly connect the positive and negative DC regulated power supplies to the corresponding ports of AD9361. In order to avoid damaging the chip by misoperation, you can connect a resistor in series to each of the two ports of AD9361 and then
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Published on 2019-3-7 10:32
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Published on 2019-3-6 18:43
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There are indeed a few pins missing, such as enable and txnrx, but these signals seem to be useful only in TDD mode, and then I configured the FDD in the register.
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Published on 2019-3-6 19:42
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dreamandactual
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Published on 2019-3-7 10:32
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The data is connected between FPGA and AD9361 through FMC, so it is not easy to operate.
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Published on 2019-3-7 11:08
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Published on 2019-3-7 10:34
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This is ok, I can try it.
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Published on 2019-3-7 11:07
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dreamandactual
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