Low resistance power distribution circuit
Source: InternetPublisher:jikai233 Updated: 2010/04/27
As shown in the figure is a low-resistance power distribution circuit diagram, in which R is the internal impedance of the battery, RL1 ~ RLn are the loads of each branch; F1 ~ Fn are the fuses of each branch, F0 is the battery fuse, and the two thick lines above and below represent the summary Liupai. If switch S is short-circuited, assuming that RL1 is short-circuited, before F1 is fused, the internal impedance of the battery is much greater than the resistance of F1, and the voltage between N and R will drop to a very low voltage. At the same time, the current in the circuit is basically is determined by the battery voltage and the internal resistance of the battery, so the short-circuit current is extremely large. When F1 fuses, because the short-circuit current before F1 fuses is large and the current change rate di/dt is also large, the induced potential L×di/dt generated on the equivalent inductance at points N and R will form a large spike. At this time, the voltage between N and R first drops to zero in an instant, and then generates a peak high voltage. These will have an impact on other branch loads in the entire system connected to the same bus. In low-impedance power distribution, each shunt load is not completely independent, and the use of multiple shunts is not conducive to effectively improving the reliability of the communication system.
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