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Hysteresis Comparator [Copy link]

 
How to calculate the two points G1 and G2 in the picture

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微信图片_20180129143258.jpg
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According to this circuit, can it be calculated? According to this circuit, it can be calculated, but the accurate calculation is quite troublesome. Swap the amplifier's non-inverting input and the inverting input, and connect the variable resistor R1 (R2) to the amplifier's non-inverting input, and form positive feedback with the resistor marked with "battery voltage" and other resistors to divide the voltage. There can be several "other resistors", including the resistor connected in parallel with the two capacitors, the resistor that supplies power to the voltage regulator tube... and R1 and R2 will affect each other (that is, the two amplifiers will affect each other depending on their state). In addition, the two capacitors will greatly slow down the speed of the comparator flipping. Therefore, if you want to apply it in practice, it is better to modify this circuit.  Details Published on 2018-1-29 18:10
 

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How to calculate the circuit in Figure 2
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This textbook was written by the canteen chef, right? Take a closer look yourself, is that a hysteresis comparator?  Details Published on 2018-1-29 15:20
 
 

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It is the value of the op amp output voltage divided by the two resistors at the back. Since the op amp here works in the comparator state, its output should be a value close to its power supply voltage. The specific value should be checked in the data sheet after selecting the model.
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mind123 posted on 2018-1-29 14:36 How to calculate the circuit in Figure 2
Was this textbook written by the canteen chef? Take a closer look yourself, is that a hysteresis comparator?
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maychang posted on 2018-1-29 15:20 Is this textbook written by the canteen chef? Take a closer look yourself, is that a hysteresis comparator?
How do you analyze it specifically?
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The output end is connected to the inverting input end of the amplifier through the variable resistor R1 (R2). This is negative feedback, but how can it be "hysteresis"?  Details Published on 2018-1-29 16:19
 
 
 

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gmchen posted on 2018-1-29 15:17 It is the value of the op amp output voltage after being divided by the two resistors behind it. Since the op amp here works in the comparator state, its output should be a value close to its...
Is there a specific calculation formula?
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The 4th poster is right, this circuit should use a hysteresis comparator, but the circuit is obviously wrong, it is an amplifier, not a comparator.
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This post was last edited by gmchen on 2018-1-29 16:15 As long as the positive and negative input terminals of the op amps in the figure are swapped, both op amps will work in the hysteresis comparator state. However, in that case, the explanations in the article are reversed. To comply with the explanations in the article, the feedback resistor needs to be connected between the op amp output and the non-inverting input terminal.
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mind123 posted on 2018-1-29 15:39 How to analyze it specifically?
The output end is connected to the inverting input end of the amplifier through the variable resistor R1 (R2). This is negative feedback, but how can it be "hysteresis"?
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maychang posted on 2018-1-29 16:19 The output end is connected to the inverting input end of the amplifier through the variable resistor R1 (R2). This is negative feedback, but how can it be "hysteresis"?
According to this circuit, can it be calculated?
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According to this circuit, can we calculate? According to this circuit, we can calculate, but it is quite troublesome to calculate accurately. Swap the amplifier's in-phase input and inverting input, connect the variable resistor R1 (R2) to the amplifier's in-phase input, and connect it to the resistor marked with "battery voltage" and other resistors.  Details Published on 2018-1-29 18:10
 
 
 

2w

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mind123 posted on 2018-1-29 17:08 According to this circuit, can it be calculated?
According to this circuit, can it be calculated? According to this circuit, it can be calculated, but the accurate calculation is quite troublesome. Swap the amplifier's non-inverting input and the inverting input, and connect the variable resistor R1 (R2) to the amplifier's non-inverting input, and form positive feedback with the resistor marked with "battery voltage" and other resistors to divide the voltage. There can be several "other resistors", including the resistor connected in parallel with the two capacitors, the resistor that supplies power to the voltage regulator tube... and R1 and R2 will affect each other (that is, the two amplifiers will affect each other depending on their state). In addition, the two capacitors will greatly slow down the speed of the comparator flipping. Therefore, if you want to apply it in practice, it is better to modify this circuit.
This post is from PCB Design
 
 
 

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