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Relationship between the resolution F0 in DFT and the signal record length T0 [Copy link]

Could someone please explain the relationship between the resolution F0 in DFT and the signal record length T0 ? It would be best if there is a derivation and explanation of the formula. Thank you.
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I don't know what the record length T0 you are talking about is. It is probably the N of the N-point DFT. The smaller 1/NT is, the higher the resolution is. T determines aliasing. Of course, the smaller the better. If you want to avoid aliasing and have high resolution, you can only increase N and fill it with zeros.  Details Published on 2006-11-29 17:26
 

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w0=2pi*f,wd=T*w0,and because wd=(2pi/N)k,==>w0=(2pi/NT)k,where 1/NT is the resolution. I just learned DSP this semester,so if I am wrong,I'm sorry.
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I don't know what the record length T0 you are talking about is. It is probably the N of the N-point DFT. The smaller 1/NT is, the higher the resolution is. T determines aliasing. Of course, the smaller the better. If you want to avoid aliasing and have high resolution, you can only increase N and fill it with zeros.
This post is from DSP and ARM Processors
 
 
 

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