esp-idf4.4 can execute (defalut) C11 standard function nested definition. What are the applications?

damiaa

esp-idf4.4 can execute (defalut) C11 standard function nested definition. What are the applications? [Copy link]

 

I was thinking about something today, and I checked and found that esp-idf4.4 can execute (defalut) C11 standard function nested definition. What are the applications? Please help me

#include"stdio.h"
int main(void)
{
    int x=0,y=0,z=0,i=5;
    auto pt(int x,int y,int z){
        printf("x is %d,y is %d,z is %d\n",x,y,z);
        printf("x+y+z is %d\n",x+y+z);
    }
    while(i){
        x++;y+=2;z+=3;
        pt(x,y,z);
        i--;
    }
}

damiaa

Switch can also be played like this

#include <stdio.h>
int main(int argc, const char * argv[])
{
    int a = 1;
    int c = 10;
    switch(a)
    {
        // 这条case语句是合法的，并且与case 1等效
        case 1 ... 1:
            printf("a = %d\n", a);
            break;
        // 这条case语句中的范围操作符的左操作数大于右操作数，
        // 因此它是一个空条件范围，这条case语句下的逻辑永远不会被执行
        case 2 ... 5:
            puts("Hello, world!");
            break;

        case 8 ... 10:
        puts("Wow!");
            break;
        default:
            break;
    }
    char ch = 'A';
    switch(ch)
    {
        // 从'A'到'Z'的ASCII码范围
        case 'A' ... 'Z':
            printf("The letter is: %c\n", ch);
            break;
        // 从'0'到'9'的ASCII码范围
        case '0' ... '9':
        printf("The digit is: %c\n", ch);
        default:
            break;
    }
}

nmg

damiaa posted on 2023-6-7 10:42 Switch can also be played like this #include int main(int argc, const char * argv[]) { ...

I guess programmers don't like to use this kind of additional gameplay.

Afraid that some compilers are incompatible

damiaa

nmg posted on 2023-6-7 18:38 I guess programmers don’t like to use this kind of added gameplay, for fear that some compilers are incompatible

I think it's still interesting