4250 views|3 replies

16

Posts

0

Resources
The OP
 

Urgent help!!! About the calculation of the inductance of the switching power supply transformer [Copy link]

 

I would like to ask the experts, I read in a book that the transformer inductance L = AL*N^2, is this formula applicable to all topologies?

Is this also the calculation for push-pull transformers?

Thank you so much!

Latest reply

Usually, the number of winding turns is determined first, and the inductance is sufficient as long as the excitation current is not too large. You can even try to wind out the designed number of turns first, and then use an inductance meter to measure whether it meets the requirements.   Details Published on 2021-4-19 18:51
 
 

1

Posts

0

Resources
2
 

I also want to know the result

 
 
 

2w

Posts

0

Resources
3
 

The transformer inductance is not very important.

The inductance of the transformer determines the excitation current, and the excitation current only needs to be smaller than the design value (in other words, the inductance is larger).

The number of turns is more important. If there are too many turns, the window cannot be wound. Although the maximum magnetic flux density in the core will be smaller with more turns, the iron loss will be smaller and the heat will be less.

 
 
 

2w

Posts

0

Resources
4
 

Usually, the number of winding turns is determined first, and the inductance is sufficient as long as the excitation current is not too large. You can even try to wind out the designed number of turns first, and then use an inductance meter to measure whether it meets the requirements.

 
 
 

Find a datasheet?

EEWorld Datasheet Technical Support

Copyright © 2005-2024 EEWORLD.com.cn, Inc. All rights reserved 京B2-20211791 京ICP备10001474号-1 电信业务审批[2006]字第258号函 京公网安备 11010802033920号
快速回复 返回顶部 Return list